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Use the graph to find the limit (if it exists).
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- 1. lim x-> -7 f(x)= 2. lim x-> -3 f(x) = 3. lim x->-2- f(x)= 4. lim x-> 1 f(x) = 5 lim x->3+ f(x) = 6. lim x->8 f(x) =2. Let g(x)= {-1/5x + 2, x<0 -2, x=0 x+2, x>0. Does the lim g(x) x→0 exist? If yes, give its value. If not, why?lim f(x) x--> 3, where f(x) = {2(x+1), if x < 3 or 4, if x = 3, or x^2 - 1, if x > 3} piecewise.they have the limit as 8? why?