y 2 -27 27 6 -8E 2.

Q: (6.47) (T4)-(r-3.6)

A:

Q: -25 (1+j2 2-j5 ) = 57 + j24 2 \3+j4

A: We need to simplify the expression -2521+j23+j4-2-j5-j and show that it is equal to 57+j24 Consider,…

Q: h (y) — Зу 6 — 8у 3 + 9у 1 -9- |

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Q: Name a right angle.

A:

Q: y" - 8y + 25y = 0; y(0) = 0, y'(0) = 3

A: y''-8y'+25y=0; y(0)=0, y'(0)=3 We have to solve it using Laplace transform.

Q: -22°y+3ry3 (a, y) # 0 0, (x, y) = 0. ||

A: Given,       f(x, y)=-2x3y+3xy3x2+y2,x, y≠0, 00,(x, y)=0, 0

Q: 6. -x² and y = 0 25 y = 6

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Q: y = /5 + x², y = 0, x= 0, x = 2

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Q: 2) y' – 10y + 25y 24te y(0) = –2, -10; - = (0)fi

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Q: -1 1 3 y - 13 15 13 -97

A:

Q: 74.(z-2y) -3z (12) |

A: To find the value of the given expression (z-2y)2-3z3(12) at x=3, y=-2, z=-1

Q: 8) y=-1 +2cos 0 3 37 37C 2 2.

A: Given query is to graph the function.

Q: 8.) y" +2y' +5y = 3e 2* ; and y(0) = y'(0) = 1

A:

Q: (a®j3 (7а)? 2 (-3a*)³ 3 3

A: The explanation of answer as follows

Q: oy-3ゾィ Ye y6-8 Ya) = 2 , Ve): 7 + 2 Yu)= 7

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Q: 8. y′′+4y′+3y=0,y(0)=2,y′(0)=−1

A: Given: y"+4y'+3y=0, y0=2, y'0=-1 for solving this we solve characteristic equation given below…

Q: 6. y"-10y'+25y= 0, y(0)=1; y'(0)= 2

A:

Q: 12) x - y> 2

A: To graph x-y>2

Q: 2e -se' 3co 3こ0

A: Given, 2e2x-5ex-3=0

Q: 4. y" + 16y = 0 (0) = 0, y (0) = 2

A:

Q: ху " +5у' + у - 0 3. y 11 %3D

A: Solution: Given Equation in form of A second Eular homogeneous Differential Equation. Rewrite the…

Q: 4) 3) 2v2 45 4V2 45° y to search

A:

Q: 11 7 Find Y 12 2r₁²³² + y² = 4 2

A: here is the solution

Q: y"" + 3y" +3y' + y = 0, y(0) = 7, y'(0) =-7, y"(0) = 11

A:

Q: 16 y 18 E F16 10 -10 -5 1 -18 -16

A:

Q: -3 9] 1. then A-' =

A: Inv(A) = adj(A)/|A|

Q: Evaluate the expression.

A: We have to evaluate the expressions: (a)  -26(b)  -26(c)  152·-33 We know that…

Q: 3. (0 +50°+ COD² - 4D - 8 ) y : 60e5× 3 60e 5x

A:

Q: Q4. Given that 30-3 1 0 1

A: the given matrix is A=-10130-310-1 The characteristic equation is A-λI=0…

Q: 5n 1) y=-2 + 4cos (40 6.

A:

Q: [A] 32 1 0 1 -2 13 4 ||

A:

Q: -8 -6 АУ 6 41 d N -41 2 4 X

A: Solution

Q: -2 U cale lil A-1 3. A = 3 0 12 -1 4 -21 ***

A: Please refer to the image below

Q: - 1)(z - 2)] im |z| < 1 |2|< 2 시지

A:

Q: 2ху + 6х?у — 1 y = 1-x2 — 2х3

A:

Q: 2. 2 y /0/0 II II 2/3

A:

Q: -*+ 15 = 0 4. 6. Зx3 —8 %3 12

A:

Q: 8х - 5y — 37 x = 2y + 6 Submit Answer

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Q: 10) y"-9y 0, y(0) = 2, y'(0) = 0

A:

Q: 17. y = -3Vx+2- 1 0 0(3 ) 8 2(3 ㅇ

A:

Q: 23. y = |x + 2| – 4 26. y = 4 - x + 2|

A: THe transformation of the graph is shown below see it carefully. Please find the solution below.

Q: 5. y" - 4y = 0 6. y" - 64y = 0

A:

Q: 2, (x+y+ 11 22 7 (x-4): こ12

A: We are given a system of nonlinear simultaneous equations. Both equations are conic sections so we…

Q: 33 26-6

A: Multiply both sides of given equation by -1.

Q: -1 7. S. ze³z² −1 dz Sydy .2 8.

A:

Q: Q.5) (a) Evaluate L-! 2+6s+9 (3-1)(s-2)(s–4

A: First use partial fraction then take inverse laplace transform

Q: y'''-8y=0, y(0)=4, y'(0)=5, and y''(0)=7

A: The solution of the problem is given in the next steps.

Q: -22 1 -6 1 -3 -2 a = b = 3. 3.

A:

Q: 6. y" + y' – y = 0; when y(-4) = 7,y'(-4) = 1

A: