y" − 3y' + 2y = 4e²t ; y(0) = −3, y '(0) = 5 —e2t4e2t + et 7 7 (1+t)4e²t - 7et 8e2t - 7et -e²t 4te²t et 7 7 O A) + |D O B) O D) + + 7

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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evaluate using lplace transform of derivatives

y" - 3y' + 2y = 4e²t ;
y(0) = -3, y '(0) = 5
-e²t4e²t
+
4e²t et
+
7 7
(1 + t)4e²t – 7et
7
B)
-e²t4te²t
et
+
7
7
7
A)
8e2t - 7et
D)
+
Transcribed Image Text:y" - 3y' + 2y = 4e²t ; y(0) = -3, y '(0) = 5 -e²t4e²t + 4e²t et + 7 7 (1 + t)4e²t – 7et 7 B) -e²t4te²t et + 7 7 7 A) 8e2t - 7et D) +
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