y = tan 5x, y = 2 sin 5x, 15 15 be

Q: In this item, sketch the region enclosed by the given curves. Then find the area of its region. 1.…

A: We need to find area.

Q: Find the area of the given region. y = sin x

A:

Q: Find the area of the described region. region enclosed by one petal of  r = 8 cos(9?)

A:

Q: Find the area of the region enclosed by the graphs of y = 2 sin(a) and y = 3 cos( from x = 0 to x =…

A: The area enclosed between the curves y=2sin x,  y=3cos x in the interval 0,3π4 is to be found.

Q: Find the area of the region that lies inside the first curve and outside the second curve. r= 16…

A:

Q: Find the area of the described region. region enclosed by one petal of  r = 6 cos(4?)

A: A=integration a to b 1/2r^2d(thita)

Q: Find the area of the region            Inside the lemniscate r^2 = 6 cos 2u and outside the circle r…

A: Given region inside the  r2=6cos2u and outside the circle r=3

Q: Find the area of the region enclosed by the inner loop of the curve. r = 2 + 4 sin ?

A:

Q: Find the area of the given region. y = cos x

A: To calculate Area : y = cos x Area = ∫x=0x = π/2y dx

Q: Find the area of the region Interior of r = 5(1 − sin θ)

A: Given Data The equation of region is r=51-sinθ.   The region lies under the limit of 0≤θ≤π.   The…

Q: Find the area of the region enclosed by one loop of the curve. r = 8 sin(30)

A:

Q: x² : 4ay from x 0 to x = 2a

A: We have to compute the surface area of revolution of the curve x2=4ay about the y-axis between the…

Q: Find the area of the region that is bounded by the given curve and lies in the specified sector.…

A:

Q: x = sin y, x = 0, y = 7/4, y = 3/4 %3D

A:

Q: 21. y = sin x, y = cos x, x = 0, x = 2T

A:

Q: Find the area of the region. Interior of r = 6 sin 0

A: A detailed solution is given below.

Q: Use integration to find the area of the rose curve r = cos 20.

A: Concept: Rose curve: A rose curve, commonly known as a multiform or Grandi's rose The rose's polar…

Q: Find the area of the region that lies inside the first curve and outside the second curve. r = 11…

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Q: 8) Find the area of the shaded region : y = sec? x 2+ 1 y = cos X 4

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Find the area of the region that lies inside the first curve and outside the second curv r = 15…

A: To find the area of the region

Q: Sketch the region and find the area it enclosed r = 3(1+ cos 0)

A: The area, A of the polar curve r=fθ in the interval a, b is calculated using the formula: A=∫ab12r2…

Q: Find the area of the region that lies inside the circle r = 1 utside the cardioid r = 1 – cos 0.

A: First draw both graph of the function and find the intersection point of the graph:

Q: r = sin 40

A:

Q: Find the area of the following shaded region. y = 1 y = cosx

A:

Q: Find the area of the region that lies inside the first curve and outside the second curve. r= 15 cos…

A: Given

Q: 1 the area of the region enclosed by the curve y = =, and the lines y = x and 2. Start by sketching…

A:

Q: Find the area of the region that lies inside the first curve and outside the second curve. 12 = 8…

A:

Q: Find the area of the region that lies inside both curves. r = 9 sin(0), r = 9 cos(0)

A:

Q: Find the area of the region that lies inside both curves. r = 2 + cos(0), r= 2 – cos(0)

A:

Q: Find the area of the described region. region enclosed by r = 16 sin(0)

A: Find the area

Q: (3) Find the total area of the region trapped between y = sin x and y = cos x and lines x = and x =…

A: The equation of the curves are C1: y = sin(x) C2: y = cos(x) C3: x = π4 C3: x = 214 To evaluate: The…

Q: Find the area of the shaded region in the diagram given below. y = sin(2r) 6 y = cos(x)

A:

Q: 8) Find the area of the shaded region: y = sec? x 1- y = cos x 4

A: Consider the formula for the area between the curves. From the given graph, find f (x), g (x), a and…

Q: Determine the area of the given region. y = x + sin x 3+ 2+ 1 4.

A:

Q: Find the area of the region inside the circle r= 32 cos 0 and to the right of the vertical line r= 8…

A:

Q: Find the area of the shaded region shown in the graph. Ay y = 27 sin x 27 y= 27 cos x

A: Solution :-

Q: 1. Sketch the region enclosed by the given curves. Find the area of the region. y = Va, y = r2, and…

A: The region is bounded by y=x, y=x2 and x=2

Q: Find the area of the region enclosed by the given curves. y = 8 cos(pi x),    y = 12x2 − 3

A:

Q: Find the area of the region that lies inside the first curve and outside the second curve. r= 14 cos…

A:

Q: Consider the region bounded by the curves y = 0, r = -1, r = 1, and 1 (r² + 1)3/2" Find the area A…

A:

Q: For what values of m do the line y = mx and the curve y = x/(x² + 1) enclose a region? Find the area…

A:

Q: Find the area of the region enclosed by one loop of the curve. r = sin(40)

A: This question is about application integral

Q: Graph the given curve and find the area of the region enclosed by one loop of the curve. r = 4 sin…

A:

Q: Find the area of the region that is enclosed by the cardiod r = 12 + 12 sin 0.

A: form a integral then solve

Q: ) Let D be the region located in the first quadrant of R² between the two circles of radii 1 and 4…

A: As per our guidelines, we are supposed to solve only first question. Kindly repost other question as…

Q: Find the area of the region that lies inside the first curve and outside the second curve. r = 4 − 4…

A:

Q: Find the area of the region enclosed by one loop of the curve. r = 4 sin(70)

A:

Q: Find the area of the region that lies inside both curves. r = (3)1/2 cos(θ),    r = sin(θ)

A: Calculate the value for intersection points and the values for theta where both the value for both…

Q: 7. r a sin 3 e

A: Explanation: Given that,  r=asin3θ  Here we will put  r=0sin3θ=0⇒3θ=0 or π⇒θ=0 or π3

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.