y = VT - x y = The area of the shaded region can be found by integration with respect to x, or by integration with respect to y. What are the considerations? Choose one for each answer box we'll need to consider one integrand for the left part of the region and another for the right part of the region, since the top v function changes If we integrate with respect to x, [ Choose ] OR we'll need to express the given functions in terms of y, and form an integrand by | subtracting: (rightmost-leftmost) If we integrate with respect to y, [ Choose ]

y = VT - x y = The area of the shaded region can be found by integration with respect to x, or by integration with respect to y. What are the considerations? Choose one for each answer box we'll need to consider one integrand for the left part of the region and another for the right part of the region, since the top v function changes If we integrate with respect to x, [ Choose ] OR we'll need to express the given functions in terms of y, and form an integrand by | subtracting: (rightmost-leftmost) If we integrate with respect to y, [ Choose ]

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)

6th Edition

ISBN:9781337111348

Author:Bruce Crauder, Benny Evans, Alan Noell

Publisher:Bruce Crauder, Benny Evans, Alan Noell

ChapterA: Appendix

SectionA.2: Geometric Constructions

Problem 10P: A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in...

See similar textbooks

Similar questions

A soda can has a volume of 25 cubic inches. Let x denote its radius and h its height, both in inches. a. Using the fact that the volume of the can is 25 cubic inches, express h in terms of x. b. Express the total surface area S of the can in terms of x.
Sketch the region of integration for the double integral given by integral 0 to ln2and e^x to 2 dydx and change its order of integration. Verify your answer by evaluating both the integrals
Find the eres of the region in two ways. a) using integration with respect to x. b) using geometry
Sketch the region enclosed by x+y2=30 and x+y=0 we know that when favoring convenience you integrate with respect to y and the lower limit of integration is -5 and the upper limit is 6 Now find the area of the region by integrating
2. Verify using the Integration (preferably integration by parts if possible) Techniques each of the equalities a and b :
1) sketch the region of integration of the integral. 2) change the order of integration and calculate the integral.
Rotate area between y =6-X and y= x^2-6x about X-axis. Compute the volume (Washer Method)
sketch the described regions of integration. 1 ≤x ≤ e2, 0≤ y ≤ ln x
I found a textbook example which intergrates an area function to find the volume of a solid of revolution bounded by the curve f(x) = (x-1)2 about the x-axis and the lines x=0 and x=2 using the disk method. The example shows a final solution change of intergration interval to x=1 and x=3 to arrive at the answer of 242pi/3 instead of the original interval x=0 and x=2? Would you show me step-wise how this was done or why it was necessary?
Evaluate the integrals. The integrals are listed inrandom order so you need to decide which integration technique to use. ∫y3/2(ln y)2 dy
39. Find the antiderivative: Hint: use integration by parts ( |udv= uv-|vdu ) | represents the antiderivative sign
find the area of the region bounded by y = x+2 and y=x^2.Use double integral to solve the question.