I don't understand why y= c3(cosay-cotay) when c4=cotay

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I don't understand why y= c3(cosay-cotay) when c4=cotay

6:45 PM Tue Oct 26
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M G aryan - ( M (56,349) - s...
Google
XLaplace equ...
Pushpa Hari...
I.facebook.c..
guH iur uv
Х (х)
= c1 cosh ax + c2 sinh ax (8)
At boundary conditions u (0, y) = 0 and u (a, y) = 0, so the value of c, is 0 als
Substitute c1 = 0 in the equation (8),
X (x) = c2 sinh ax (9)
Substitute 2 =
-a? in equation (3),
Y" + a?Y = 0
The general solution of the above equation is,
Y (y) = c3 cos ay + c4 sin ay (10)
ди
At boundary conditions u (0, y) = 0, u (a, y) = 0 and
= 0, c4 = -c3 cot c
— — Сз соt
ly=0
Substitute c4 = -c3 cot ay in the equation (10),
Y (y) = c3 (cos ay – cot ay) (11)
-
Substitute the value of X (x) from equation (9) and the value of Y (y) from e
и (х, у) — с2сз sinh ax (сos aу — cot ay) (12)
ди
At boundary conditions u (0, y) = 0, u (a, y) = 0 and = 0, c2c3
= 0, c2c3 = 0
ду
=0
Substitute c2c3 = 0 in the equation (12),
и (х, у) — 0
Transcribed Image Text:6:45 PM Tue Oct 26 * 15% O AA bartleby.com M G aryan - ( M (56,349) - s... Google XLaplace equ... Pushpa Hari... I.facebook.c.. guH iur uv Х (х) = c1 cosh ax + c2 sinh ax (8) At boundary conditions u (0, y) = 0 and u (a, y) = 0, so the value of c, is 0 als Substitute c1 = 0 in the equation (8), X (x) = c2 sinh ax (9) Substitute 2 = -a? in equation (3), Y" + a?Y = 0 The general solution of the above equation is, Y (y) = c3 cos ay + c4 sin ay (10) ди At boundary conditions u (0, y) = 0, u (a, y) = 0 and = 0, c4 = -c3 cot c — — Сз соt ly=0 Substitute c4 = -c3 cot ay in the equation (10), Y (y) = c3 (cos ay – cot ay) (11) - Substitute the value of X (x) from equation (9) and the value of Y (y) from e и (х, у) — с2сз sinh ax (сos aу — cot ay) (12) ди At boundary conditions u (0, y) = 0, u (a, y) = 0 and = 0, c2c3 = 0, c2c3 = 0 ду =0 Substitute c2c3 = 0 in the equation (12), и (х, у) — 0
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