How did he get the Step 2 value inside the line Taking the z-transform of (1) Z [y (k + 2) – 9y (k + 1) + 20y (k)] =Z [u (k)] = Z [y (k + 2)] - 9Z [y (k + 1)] + 20Z [y (k)] = Z =? {Y(z) – y(0) - y(1)z-} – 9z {Y(z) – y(0) {:: u sin g formula} → ? {Y(z) – 6 – 24z-1} – 9z {Y(z) – 6} + 20Y( | > Y(z) [z – 9z + 20 – 6z – 24z + 54z = %3D z) z – 9z + 20 = + 6z – 30z → Y(:)(: -4)(:- s) 6z-36z+31z z-1 Y(z) 6z2-36z+31 %3D (z-1)(z-4)(z-5)

How did he get the Step 2 value inside the line Taking the z-transform of (1) Z [y (k + 2) – 9y (k + 1) + 20y (k)] =Z [u (k)] = Z [y (k + 2)] - 9Z [y (k + 1)] + 20Z [y (k)] = Z =? {Y(z) – y(0) - y(1)z-} – 9z {Y(z) – y(0) {:: u sin g formula} → ? {Y(z) – 6 – 24z-1} – 9z {Y(z) – 6} + 20Y( | > Y(z) [z – 9z + 20 – 6z – 24z + 54z = %3D z) z – 9z + 20 = + 6z – 30z → Y(:)(: -4)(:- s) 6z-36z+31z z-1 Y(z) 6z2-36z+31 %3D (z-1)(z-4)(z-5)

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter7: Eigenvalues And Eigenvectors

Section7.CM: Cumulative Review

Problem 5CM: Find the kernel of the linear transformation T:R4R4, T(x1,x2,x3,x4)=(x1x2,x2x1,0,x3+x4).

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