YA (1, 25) 10 (-4, 0) (6, 0) -8 8 X 10 4.

Q: i) trunc (5.9)(3.5)]-[]-L8.007-5.63 TC

A:

Q: а. 42(x – 2) = 32* -2 b. 2(3*-2)= 18

A:

Q: 11) y=7x-21 y = 8x - 24 A) (-5, 0) B) (0, –5) C) (5, 0) D) (3, 0)

A: Consider the system  y=7x-21                            ..............(1)  y=8x-24…

Q: i '2/3

A: Given: i23 we know that amn=am1n

Q: iGO 2. -/3 2/3 1/2

A:

Q: ||v|| = 4, 0 = 3.4°

A: Given query is to find component of v.

Q: 8 X = - 24

A: We have8x = -24Divided by 8 on both side, we get

Q: 7 y = 0, x1 = 1, x2 = 2

A:

Q: U-5/7=62/3

A: Solve the equation for U as follows.

Q: 2h-3>15

A: 2h-3>15  add 3 both sides 2h-3+3>15+3

Q: 15. (2 – 10e-2) 0.32

A:

Q: -1 2 4, 3 A = -1 2

A:

Q: 5. マ*= 7x -11 4x-2 20 35

A:

Q: y = /5 + x², y = 0, x= 0, x = 2

A:

Q: 4 (-2, -2) (0,-2) 55. (-1, -3)F 4.

A:

Q: 2 3) (6-1)°(st3)

A: We find inverse laplace transform of given problem.

Q: 20+1/5c=-7

A: Ans:            -20+15c=-7  cross multiply⇒-20+1=5c-7                          ⇒-19=-35c…

Q: a² +7< 3 - |5x - 3|.

A:

Q: 2 2 R = -3

A:

Q: 9. X y 8. -18 8, 2. 5. 2.

A: We have write equation of straight line from two point from.

Q: 8 23. 60/3 – 3 -

A: Given: 603-83 for simplify it we take L.C.M. and solve it

Q: Find the determinant of

A: Find the determinant of A

Q: (v) y = -3 (vi) y = - 4 (vii) y =5 (ir) 7 = - 3 (x) 7 = -4 (ri) 7 =5

A:

Q: 2. 9. y =- 4.-72

A: This is a problem of equilibrium and stability analysis.

Q: 3. 3(22+7)-

A:

Q: 5 + 2 = - y-2 8. 5 15 3

A: Given that,

Q: 9 5/12 - 3 2/3 =

A: Case 1: Let the given number be in mixed fraction notation.

Q: 3(15t-17)+2(t-45)=0

A:

Q: 2e -se' 3co 3こ0

A: Given, 2e2x-5ex-3=0

Q: 2{18-(5+32)/7}

A: First put 3^2=9 and work with parenthesis.

Q: 2 4 .2 + 2+ jo to

A: given that                                               4-j2j2+2+j0 we know that…

Q: 2zdz 21.17. So z²–4)² 2

A: The solution is given below in the next step:

Q: Solve by eliminating variables:

A: We have to solve the equation by eliminating the variables   The given system of equation is…

Q: -5+2(8-12)

A: Use PEMDAS rule to simplify.First we work with the parenthesis. In it 8-12=-4

Q: [A] 32 1 0 1 -2 13 4 ||

A:

Q: 30.3x+ダ35 GA-yュ4 %23

A:

Q: -5 4 -2 -7 -8 2.

A:

Q: d. (-1,4) 11π b. (-3,) c. (3,- 6 5π 2

A: (r, θ)=-3, 11π6(x, y)=(r cosθ, r sinθ)        =-3cos11π6, -3 sin11π6       =-332, 32In the second…

Q: 25. 부 < 프등 1-a 4 2r-2 3

A: In this question , we can solve for 'x' .

Q: 4х- 10 5y - 4 36 18

A:

Q: 4 3 2 R 4 -3-2 -1S이 3. 4. -2 -4 5. 1, 1.

A:

Q: B. 8- 4- -8 8. -8-

A: Find eacph length of xy, yz and zx  separately and add them

Q: -7+2+6+5=v

A:

Q: -22 1 -6 1 -3 -2 a = b = 3. 3.

A:

Q: [ 2, l , 2 ] · ( 3 , - 1 , 0 )

A: