(y>-- (2x-y 2-3 AALAM

Q: y" – 4y'+5y = xe²*, y(0) =-1, y'(0)=0.

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Q: y=(2e+1) (x+2)* y= ?

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Q: y(x) = C1x"+ C2xP, evaluate a + B2). x²y" – 19xy' + 84y = 0, x > 0. -

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Q: y = 4e2x + xe2x; y" - 2y' + 1 = 0. Yes O No

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Q: -t 9-y" + 2y +y = 3e¯t

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Q: x3 3. y =- (х-5)(x+1)

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Q: 1. y = x³ -x?

A: Note: - Since you have asked multiple question, we will solve the first question for you. If you…

Q: (Dª + 3D³ – 6D² – 28D – 24)y = 0 -

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Q: x²yy' = (y² - 1)3/2

A: Given that, x2yy'=y2-132 We can solve this by using variable separable method. ∫xn dx=xn+!n+1+C

Q: y = 3x/2 from x = 0 to x = 335 243 1 335 162 335 3.

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Q: in general form x² – 2x – 6y – 5 = 0? 5 A B y- -

A: The given equation of the parabola is: x2-2x-6y-5=0⇒6y=x2-2x-5⇒6y=(x2-2x+1)-6⇒6y=(x+1)2-6…

Q: -0.2 Y + T = 20 -0.6 Y + C = 70 Y - C = 30 %3D

A: Solution

Q: face at x = 0. y² – 4z? = 4 -12 -8 12 -12 -8 -12 6r 4- 2 -6 4. 4. 4.

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Q: - -x, x-2 4) h(x) = y 16 2

A: We will draw the graph of given function by taking arbitrary values of x , and then We get output…

Q: y=x²+2x when x=2 and Ax=0.05

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Q: Vr' +y? ydzdydx x² + y? +z? x²+y² 3 Jo Jo

A: Given:           ∫35∫0x∫0x2+y2ydzdydxx2+y2+z2       ∫0x2+y2yx2+y2+z2dz        =y∫0y2+x21y2+x2+z2dz…

Q: y2(1+p2)=x+yp what is y?

A: Given data:     The given expression is: y2(1+p2)=x + yp.   The given expression can be written as,

Q: y² 49 1 y? /-

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Q: 2. (x* + y?)(xdy + ydx) - ху(xdx + ydy) -0

A: A detailed solution is given below

Q: *+ y = e2t ; y(0) = 0 2.

A: Given,  dydt+y=e2t; y(0)=0 We can write it as y'+y=e2t

Q: y =x? +6 2. at x-2 4.ア=+5 at x-1

A: Put values of x and find y

Q: 3. x = y? ,x = -2y² + 3

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Q: y=(x^2+1)^4 y`(1)=?

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Q: -4x 2.) y = required:a) find the value of y if x = 1

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Q: (4) y (ª) + 2y "+ y =(x -1)°

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Q: x²y+ 2xy = x + y ise y =?

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Q: y" + 19y'+ 49y=0 i ycuD =-1 y'(-4)=5 t.

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Q: xy2 = 8 at (2,2)

A: Substitute x=2 and y=2 in the given function xy2

Q: y′ = t2 + y2

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Q: The Yp of (D²+D) y=20

A: Given (D2 + D) y = 20 To find yp(x)

Q: a. x²y' +3xy ==, y(1) = -1

A: Since you have posted multiple questions, but according to guidelines we will solve first question…

Q: 3x2 – ex y' 2y – 5 ;y(0) = 1

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Q: y" — y' — 6y = t²e³t — 4t², y(0) = 0, y' (0) = -1

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Q: x2 +y? +z? - 4x + 8y – 2z = - 12

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Q: y'e +x ア-2pe 1/

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Q: Y+ 3Y'-10Y= x(e*+) 107=

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Q: Verfy ST F:(x²ty?)£- 2x ta; y=0; y>b Ans; -49b

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Q: y" - y' - 6y=t²e³t — 4t², y(0) = 0, y' (0) = -1

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Q: - y = 2cot² x+1

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Q: (x2D2 + xD - 41)y = 1/x?

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Q: y? -dy (y2–4) 7

A: We have to find solution

Q: Evalunte: 2x-3y'+2 when X=2 and y=-3

A: To evaluate the given expression

Q: 4y? - 7y - 12 dy y(y + 2)(y - 3)

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Q: (3ry- 1) dr + (x³ + 6y – y?) dy = 0 y(0) = 3

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Q: (a) y = x2 – 2 and y = 2 -

A: Since you have asked multiple question, we will solve the first question for you as per our guide…

Q: Find y' when ye2x= 3y+ x and y(0)=3 A -4 -6 -5

A: