You are a researcher studying the lifespan of a certain species of bacteria. A preliminary sample of 35 bacteria reveals a sample mean of = 74 hours. The population standard deviation is known to be 5.8 hours. You would like to estimate the mean lifespan for this species of bacteria to within a margin of error of 0.5 hours at a 90% level of confidence. How many more bacteria should you sample to achieve a 0.5 hour margin of error? n bacteria

Q: The population standard deviation for the height of students from STAT class is three inches. If we…

A: The confidence level is 98%, population standard deviation is 3, and margin of error is 1.

Q: The mean marathon finishing time for men and women was 268 minutes and 280 minutes respectively.…

A: From the given information, The mean marathon finishing time for men and women was 268 minutes and…

Q: A researcher knows that the average height of Filipino women is 1.525 meters. A random sample of 32…

A: Given Standard deviations=0.10 Mean=1.56 n=32

Q: A sample of 71 college students yields a mean annual income of $3595. Assuming that the population…

A:

Q: A​ half-century ago, the mean height of women in a particular country in their 20s was 63.8 inches.…

A: Given data,μ=63.8σ=2.51If n=28P(X≥65.08)=?

Q: An advertising executive wants to estimate the mean amount of time that consumers spend with digital…

A: It is given that confidence level is 0.95, standard deviation is 44 and margin of error E is 4.

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Given :  We are interested in estimating the mean weight of the local adult population of female…

Q: An advertising agency has stated that 20% of all television viewers watch a particular program. How…

A: From the provided information, An advertising agency has stated that 20% of all television viewers…

Q: statistics professor reported that the mean score in a recent quiz is 72 and the standard deviation…

A: Solution

Q: Loretta, who turns  91  this year, has heard that the mean systolic blood pressure among the…

A:

Q: A researcher works on a study that has a population standard deviation of 0.75, a sample mean of 86,…

A: Given Data: x¯=86σ=0.75n=65   z-value corresponding to 95% Confidence Interval=1.96

Q: An advertising executive wants to estimate the mean amount of time that consumers spend with digital…

A: Here we've given the following values. Standard deviation , σ = 43 minutes. Margin of error , E = ±…

Q: You are interested in estimating the the mean weight of the local adult population of female…

A:

Q: Among 157 African-American men, the mean systolic blood pressure was 146 mm Hg with a standard…

A: From the provided information, Sample size (n) = 157 Sample mean (x̅) = 146 mm Sample standard…

Q: Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly…

A: Givensample sie(n)=18sample mean(x¯)=128standard deviation(s)=22α=0.05

Q: According to one source, the average yearly cost to house a prisoner in the United States in a…

A: State the hypotheses.

Q: Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly…

A: The random variable systolic blood pressure follows normal distribution. The population mean is 115…

Q: A researcher wanted to determine the mean number of hours per week the typical person watches…

A: Obtain the required sample size: The given confidence level 100*(1–α)% = 95%. The critical value is…

Q: An advertising executive wants to estimate the mean amount of time that consumers spend with digital…

A: a) The sample size is 117 and it is obtained below: From the given information, the population…

Q: You are interested in estimating the the mean weight of the local adult population of female…

A:

Q: You are interested in estimating the the mean weight of the local adult population of female…

A:

Q: A candy manufacturer has replaced 5.17% of their chocolate bars with a new mystery flavor. Find the…

A: Given: Sample size (n) = 424 p(chocolate bars with a new mystery flavor) = 5.17% = 0.0517

Q: A tire company claims the lifetimes of its tires average 50,000 miles. The standard deviation of…

A: Given Information: Mean = 50,000 Standard deviation = 5000 Sample size (n) = 100 (c) If the test is…

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Given that the population standard deviation is 17 pounds. Confidence level is 96% Margin of error…

Q: According to Consumer Expenditures, the average consumer spent $1729 on apparel and services in…

A:

Q: The school head observes an increase of internet expenditures of learners for months already with a…

A: Given : Standard deviation (σ)=15 Confidence interval (C.I)=99% α=0.01 Margin of error (E)=2.00

Q: Suppose on a chicken farm a random sample of 30 chickens were selected. The mean weight of the 30…

A: Given Data: μ=5.8σ=0.085   We know that X¯~ Normal μ, σ2n

Q: One​ year, the mean age of an inmate on death row was 40.7 years. A sociologist wondered whether the…

A:

Q: A population has a mean of 75 and a standard deviation of 15. If you randomly sample 9 people from…

A: Mean = 75 Standard deviation = 15 Sample size = 9

Q: The average weekly income of a U.S. student worker is $200 with a standard deviation of 50. If a…

A: Standard error of sample mean=σn, where σ is the population standard deviation and n is the sample…

Q: Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly…

A: As per bartby gaidline excite have to ans fast three subpart part only dear student please upload…

Q: The director of research and development is testing a new medicine. She wants to know if there is…

A: Assume that μ is the true average time the medicine relives pain.

Q: On average, Americans have lived in 4 places by the time they are 18 years old. Is this average more…

A:

Q: a group of mathematics teachers wants to estimate the average computational skills of the students…

A: From the provided information, Population standard deviation (σ) = 5 Confidence level = 95% Margin…

Q: A university dean wishes to estimate the average number of hours that freshmen study each week. The…

A:

Q: An advertising agency that serves a job radio station wants to estimate the mean amount of time that…

A: Here, σ=45, confidence level=90%, E=5.

Q: We want to know if there exists a difference in sleep between pregnant and non-pregnant Americans.…

A: From the provided information,

Q: if an average score of exams was 74 points for 24 students  the 25th student got 64 points whats…

A:

Q: stimating the the mean weight of the local adult population of female white-tailed deer (doe). From…

A: The sample size can be calculated as: n=z×σE2Here, z = desired confidence level E = The allowable…

Q: An advertising executive wants to estimate the mean amount of time that consumers spend with digital…

A: Answer - The standard deviation σ = 47 minutes. Margin of error  E = ±7  minutes                90%…

Q: A researcher wants to estimate the mean sleeping time of patients with sleep apnea. In a similar…

A: We have to find how many patients should be sampled to be 95% confident with the result accurate…

Q: Loretta, who turns 91 this year, has heard that the mean systolic blood pressure among the elderly…

A: Given: μ = 115 x¯ = 133 s = 23 ∝ = 0.05 n = 10 The test hypothesis are, H0: μ = 115 H1: μ > 115.…

Q: In the general population, the mean IQ score is 100, with standard deviation σ = 15. A random sample…

A: Given :- In the general population, the mean IQ score is 100, with standard deviation σ =15 . A…

Q: An economist would like to estimate the mean amount of money that a family spends to within $35. If…

A:

Q: 5 will be drawn from a population of test takers with a mean of 150 and standard deviation 9. Find…

A: Given that  Sample size (n) = 75 Population mean (μ) = 150 Standard deviation (σ) = 9   We know that…

Q: In order to set rates, an insurance company is trying to estimate the number of sick days that full…

A: Given that  Standard deviation = 2.4 days Confidence level (C) = 95%  The true mean differs from the…

Q: In a random sample of 6 cell phones, the mean full retail price was 517.30 and standard deviation is…

A:

Q: A leading magazine (like Barron's) reported at one time that the average number of weeks an…

A: Given data,μ=35.2σ=5.6

Q: An economist would like to estimate the mean amount of money that a family spends to within $82. If…

A: We have given that,  Margin of error (E) = 82, standard deviation (σ) = 490 confidence level (c) =…

Q: You are interested in estimating the the mean weight of the local adult population of female…

A: Obtain the sample size needed. The sample size needed is obtained below as follows :