You are given a free particle (no potential) Hamiltonian Ĥ dependent wave-functions = V₁(x, t) V₂(x, t) 2 sin(x)е -ithm + sin(27x)e¯ What would be results of kinetic energy measurements for these two wave-functions? Give only possible outcomes, for example, it is possible to get the following values 5, 6, and 7. No need to provide corresponding probabilities. = -it 2h² m sin(2x) e = ħ² d² 2m dar2 and two time- -it 2hr 2 m (1) (2)
You are given a free particle (no potential) Hamiltonian Ĥ dependent wave-functions = V₁(x, t) V₂(x, t) 2 sin(x)е -ithm + sin(27x)e¯ What would be results of kinetic energy measurements for these two wave-functions? Give only possible outcomes, for example, it is possible to get the following values 5, 6, and 7. No need to provide corresponding probabilities. = -it 2h² m sin(2x) e = ħ² d² 2m dar2 and two time- -it 2hr 2 m (1) (2)
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![You are given a free particle (no potential) Hamiltonian Ĥ
dependent wave-functions
=
-it 2h7²
m
sin(2x) e
=
V₁(x, t)
V₂(x, t)
2 sin(x)e
-ithm + sin(2x)e¯
What would be results of kinetic energy measurements for these two wave-functions?
Give only possible outcomes, for example, it is possible to get the following values
5, 6, and 7. No need to provide corresponding probabilities.
ħ² d²
2m dx2
and two time-
-it 2hr 2
m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F12f51b64-c3b4-40b6-b565-16b387e10bf1%2Fca800b7d-cad9-4f1f-80ab-2157b186942a%2Fev8ddd7_processed.png&w=3840&q=75)
Transcribed Image Text:You are given a free particle (no potential) Hamiltonian Ĥ
dependent wave-functions
=
-it 2h7²
m
sin(2x) e
=
V₁(x, t)
V₂(x, t)
2 sin(x)e
-ithm + sin(2x)e¯
What would be results of kinetic energy measurements for these two wave-functions?
Give only possible outcomes, for example, it is possible to get the following values
5, 6, and 7. No need to provide corresponding probabilities.
ħ² d²
2m dx2
and two time-
-it 2hr 2
m
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