You are looking at an old script you wrote and see this line: if [ -x /bin/ps -a -f /etc/app.conf ] In plain English, what does it say ? a) if /bin/ps is excluded from /etc/app.conf b) if the output of /bin/ps contains all the strings from file /etc/app.conf c) if /bin/ps is executable and /etc/app.conf exists d) if either /bin/ps or /etc/app.conf exists
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You are looking at an old script you wrote and see this line:
if [ -x /bin/ps -a -f /etc/app.conf ]
In plain English, what does it say ?
a) if /bin/ps is excluded from /etc/app.conf
b) if the output of /bin/ps contains all the strings from file /etc/app.conf
c) if /bin/ps is executable and /etc/app.conf exists
d) if either /bin/ps or /etc/app.conf exists
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- Write a script that converts the count amount of letters starting from the end of a given word to uppercase. The script should take the word as a string and specify the count amount of letters to convert as an integer input from the user. You can assume that the count variable will be a positive number. Steps for Completion Open your main.py file. On the first line, request the string to convert from the user. On the next line, request how many letters at the end of the word should be converted. Next, get the start of the string. Then, get the ending of the string, that is, the one we'll be converting. Then, concatenate the first and last part back together, with the last substring transformedWhy is it considered good practice to open a file from within a Python script using (a) instead of (b)? (a) with open(‘textfile.txt’,’r’) as f: f.readlines() (b) f=open(‘textfile.txt’,’r’) f.readlines() f.close() a. When you open a file using the with keyword in Python, Python will make sure the file gets closed, even if an exception or error is thrown. b. The with keyword lets you choose which application to open the file in. c. The with keyword acts like a for loop, and lets you access each line in the file one by one. d. There is no benefit to using the with keyword for opening a file in Python.can someone check why my code is not working? intergers.txt 4 7 2 5 3 #include <iostream>#include <fstream>using namespace std; int main(){int num[100],i=-1; // variable declaration to read the integer data char tx;//variable declared ifstream myFile; // input file declaration myFile.open("numbers.txt"); // Syntax for open the file and read integer.txt while (!(myFile.eof())){ myFile >> num[i]; i++; // read the integer content from the file //myFile>>tx; // read the comma}num[i] = num[i+1]; // Delete the last garbage valuecout<<"The elements in the array are "; for(int j=0;j<i;j++){ // Loop to run for all the elements in the array if(j==i-1) cout<<num[j]<<endl; // print element with new line else cout<<num[j]<<","; // print the array} myFile.close(); //close the filereturn 0;}
- Given a valid filepath, you will read a BINARY file that consists of two "columns" of double precision floating point numbers.The format is little endian. Once you have read the data plot the first column vs the second column (x axis is the first column).You should always properly label your plot!- In this case since there are no units you can title the x and y axes "x" and "y".- The title should be "Star Plot - (first.last.yy)"- Turn in this figure to scholarHint: You will know that you are plotting the data correctly if the name of this function makes sense.:param filepath::return:"""Given a valid filepath, you will read a binary file that consists of two "columns" of double precision floating point numbers.The format is little endian. Once you have read the data plot the first column vs the second column (x axis is the first column).You should always properly label your plot!- In this case since there are no units you can title the x and y axes "x" and "y".- The title should be "Star Plot - (first.last.yy)"- Turn in this figure to scholarHint: You will know that you are plotting the data correctly if the name of this function makes sense. USE STRUCT, MATPLOTLIB, AND OS MODULES IN PYTHON:param filepath::return:"""Given a valid filepath, you will read a binary file that consists of two "columns" of double precision floating point numbers.The format is little endian. Once you have read the data plot the first column vs the second column (x axis is the first column).You should always properly label your plot!- In this case since there are no units you can title the x and y axes "x" and "y".- The title should be "Star Plot - (first.last.yy)"- Turn in this figure to scholarHint: You will know that you are plotting the data correctly if the name of this function makes sense.:param filepath::return: USE THESE THREE MODULES BELOW COPY/PASTE ANSWERS WILL BE DOWNVOTED IMPORT STRUCT IMPORT MATPLOTLIB.PYLOT AS PLT IMPORT OS
- You lost me here: stdafx.h should I be creating a seperate file from here down? I don't know how to separate the coding from that down, I am confused.What output will be produced when the following lines are executed, assuming the file list.dat contains data shown (and assuming the lines are embedded in a complete and correct program with the proper include directives)? Write your answer in the box below. The file list.dat contains the following three numbers, and nothing more. 1 2 3 Output Display ifstream ins; ins.open (“list.dat”); int count = 0, next; while (ins >> next) { count++; cout << setw(next) << next << endl ;} ins.close (); cout << setw(++count) << count;What do you see when you execute "pipe1" and Why? Modify the program pipe1.cpp to pipe1a.cpp so that it accepts a command (e.g. "ls -l") from the keyboard. For example, when you execute "./pipe1a ps -auxw", it should give you the same output as pipe1.cpp. Please explain what you changed and why.(Hint: Use string functions strcpy() and strcat() to store the commands in a buffer. Your main function should be like: int main(int argc, char *argv[])) //pipe1.cpp #include <unistd.h> #include <stdlib.h> #include <string.h> #include <stdio.h> #include <iostream> using namespace std; int main() { FILE *fpi; //for reading a pipe char buffer[BUFSIZ+1]; //BUFSIZ defined in <stdio.h> int chars_read; memset (buffer, 0,sizeof(buffer)); //clear buffer fpi = popen ("ps -auxw", "r"); //pipe to command "ps -auxw" if (fpi != NULL) { //read data from pipe into buffer chars_read = fread(buffer, sizeof(char), BUFSIZ, fpi); if…
- // switch_stdout.c: demonstrates use of dup2() and dup() to redirect // standard output to a new location temporarily and then restore it. #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <fcntl.h> int main(){ int stdout_bak = dup(STDOUT_FILENO); // make a backup of stdout system("rm -f mystery.txt"); // remove file using a shell command int out_fd = open("mystery.txt", // open file mystery.txt O_WRONLY|O_CREAT, // for writing, create if needed S_IRUSR|S_IWUSR); // give user read/write permission if(out_fd == -1){ // check for errors opening file perror("Couldn't open file 'mystery.txt'"); exit(1); // bail out if open fails } printf("1. Now you see me.\n"); // print to the screen dup2(out_fd, STDOUT_FILENO); // change stdout to go to mystery.txt printf("2. Now you don't!\n"); // print goes to…I have a "user.json" file that looks like this { "something@somewhere.com": "maybe", "john@beatles.uk": "lennonj!", "paul@beatles.uk": "mccartney", "mick@rollingstones.uk": "jaggerm!" } using java script i have to parse this file and then check this email and file conbinations against user input This is the code i m using to parse the file. function lookUpCredentials(filePath, cb) { fs.readFile(filePath, (err, fileData) => { if (err) { return cb && cb(err); } try { const object = JSON.parse(fileData); return cb && cb(null, object); } catch (err) { return cb && cb(err); } }); } lookUpCredentials("./user.json", (err, data) => { if (err) { console.log(err); return; } credentials = data; }); and this is the code i m using to get input from the user app.post('/login', (req, res) => { let username =…What will be the content of 'file.c' after executing the following program? #include<stdio.h> int main() { FILE *fp1, *fp2; fp1=fopen("file.c", "w"); fp2=fopen("file.c", "w"); fputc('A', fp1); fputc('B', fp2); fclose(fp1); fclose(fp2); return 0; }