You found that the reduction formula of a certain integral is In = 180 (13x" sin (13x) + næ"-1 cos (13x) – n (n – 1) In-2] 169 1 and that I =R a sin (13x) + cos (13x) 169 What is I3? 3 - sin (13x) + 169 6 cos (13x) cos (13x) æ sin (13x) 2197 13 28561 1 -2³ sin (13x) + 169 3 -x² cos (13x) 169 x sin (13x) 2197 -cos (13x) 28561 - sin (13x) – 13 3 -x² cos (13x) + 169 x sin (13x) 2197 6 cos (13x) 28561 1 æ sin (13x) + 2197 -a³ sin (13æ) 13 3 -x² cos (13x) 169 cos (13x) - - 28561

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter9: Polynomial And Rational Functions
Section9.2: Remainder And Factor Theorems
Problem 53PS
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You found that the reduction formula of a certain integral is
In
[132" sin (13r)+ næ"-1 cos (13æ) – n (n – 1) In-2]
169
1
e sin (13x) +
cos (13x)
169
and that I
What is I3?
3
6
13
x sin (13x)
2197
x³ sin (13x) +
x² cos (13x)
169
-cos (13x)
28561
1
3
6
sin (13x) +
169
cos (13x)
x sin (13x)
2197
-cos (13x)
28561
169
1
3
x³ sin (13x)
13
6
-x sin (13x)
2197
cos (13x) +
cos (13x)
169
28561
6
1
-x³ sin (13x)
13
3
x sin (13x) +
2197
-cos (13x)
28561
-x² cos (13x)
169
Transcribed Image Text:You found that the reduction formula of a certain integral is In [132" sin (13r)+ næ"-1 cos (13æ) – n (n – 1) In-2] 169 1 e sin (13x) + cos (13x) 169 and that I What is I3? 3 6 13 x sin (13x) 2197 x³ sin (13x) + x² cos (13x) 169 -cos (13x) 28561 1 3 6 sin (13x) + 169 cos (13x) x sin (13x) 2197 -cos (13x) 28561 169 1 3 x³ sin (13x) 13 6 -x sin (13x) 2197 cos (13x) + cos (13x) 169 28561 6 1 -x³ sin (13x) 13 3 x sin (13x) + 2197 -cos (13x) 28561 -x² cos (13x) 169
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