You have a table Employee(empID,name,salary,dno). Dno is department number to which employee belongs. What is the SQL statement used to find the total of salaries payed for all employees for each department?
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- can you help me iwth these two queries in mySQL. Write a SQL statement to create a table job_history including columns employee_id, start_date, end_date, job_id and department_id and make sure that, the employee_id column does not contain any duplicate value at the time of insertion and the foreign key column job_id contain only those values which are exists in the jobs table. Write a SQL statement to create a table employees including columns employee_id, first_name, last_name, email, phone_number hire_date, job_id, salary, commission, manager_id and department_id and make sure that, the employee_id column does not contain any duplicate value at the time of insertion and the foreign key columns combined by department_id and manager_id columns contain only those unique combination values, which combinations are exists in the departments table.The following two SQL statements will produce the same results. SELECT P_DESCRIPT, P_PRICE FROM PRODUCT WHERE P_CODE IN (SELECT P_CODE FROM LINE GROUP BY P_CODE HAVING COUNT(*) >=1); SELECT P_DESCRIPT, P_PRICE FROM PRODUCT WHERE EXISTS (SELECT P_CODE FROM LINE WHERE LINE.P_CODE=PRODUCT.P_CODE); Group of answer choices A) True B) FalseBelow are three tables and their attributes: Table 1: customers ( CustomerID, CustomerName, City, Country) Table 2: orders ( OrderID, ProductID, CustomerID) Table 3: products (ProductID, ProductName, Price, SupplierID) Can you come up with a SQL statement to find all customers who ordered products from a supplier whose SupplierID is '222'. Remove duplicates
- Consider the following schema of employees working at Carlson Fabrics Ltd (CFL) and write SQL statements for the queries.Employee(emp_id, emp_name, address, age, gender, designation, department, shift, salary, transport) i. Give the name of the employees whose mode of transport to CFL is van. ii. List the details of female employees who work during day shift. iii. Display details of those employees coming from Vacoas or Mahebourg. iv. List all employees, whose name start with letter "B" and ends with "e". v. Set salary of all supervisors to Rs 35 000. vi. Display the designation of the employees, whose salary is betweeen 30000 and 40000. vii. Display details of employees, where salary is 35000 or age is greater than 30. viii. List name and department of employees, where age is greater than 45 order by salary.51. The given SQL statement is intended to either (1) list the customer numbers, customers names, and headquarter cities of customers headquartered in Los Angeles or (2) satisfy the two conditions of having a customer number higher than 1000 and being headquartered in Denver. SELECT CUSTNUM, CUSTNAME, HQCITY FROM CUSTOMER WHERE HQCITY= 'Los Angeles" Which set of lines should be added to the end of the statement to make the statement work as intended? A: (CUSTNUM>1000 AND HQCITY-'Denver'); B: AND (CUSTNUM>1000 AND HQCITY='Denver*); C:OR CUSTNUM>1000 OR HQCITY='Denver": D:OR (CUSTNUM> 1000 AND HQCITY='Denver*);Write the SQL statement that will list the city and state of all customers. If more than one customer is from the same city and state, only list that city and state once. Sort the output by state and then by city.
- Can some rewrite the following sql tables into relational algebra format? a) SELECT NoOfCopies FROM ( (BOOK NATURAL JOIN BOOK_COPIES ) NATURAL JOIN LIBRARY_BRANCH ) WHERE Title = 'The Lost Tribe' AND BranchName = 'Sharpstown' b) select count(b.No_of_copies ) from BOOK_COPIES b join LIBRARY _BRANCH l on l.Branch_id=b.bBranch_id join BOOK k on k.Book_id=l.Book_id where k.Title=’The lost tribe’ group by l.Branch_id; C) SELECT Name FROM BORROWER B WHERE NOT EXIST ( SELECT * FROM BOOK_LOANS L WHERE B.CardNo = L.CardNo ) D) select b.Title, br.Name, br.Address from BOOK b join BOOK_LOANS bl using(Book_id) join BORROWER br using(Card_no) join LIBRARY _BRANCH lb using(Branch_id) where lb.Branch_name=’Sharpstown’ and bl.Due _date=SYSDATE; E) SELECT L.BranchName, COUNT(*) FROM BOOK_COPIES B, LIBRARY_BRANCH L WHERE B.BranchId = L.BranchId GROUP BY L.BranchName f) select b.Title ,bc.No_of_copies from BOOK b join BOOK_AUTHORS ba using(Book_id) join BOOK_COPIES bc using(Book_id) join…Answer the given question with a proper explanation and step-by-step solution. I wrote a spark SQL query that returns the top 100 users, however, I need to show name rather than user_id. What am I missing? My code is shown below: def users_top_100_tip_count():return spark.sql("""\SELECT tip.user_id, count(*) as tip_countFROM tipLEFT JOIN userON tip.user_id = user.user_idGROUP BY tip.user_idORDER BY tip_count DESC, user_id ASC LIMIT 100""") example of my expected output: +--------+---------+ | name|tip_count| +--------+---------+ | Weifong| 167| | Alice| 42| | Bob| 42| | Jamal| 3| +--------+---------+Write SQL statements to answer the following questions using Assignment 3’s schema (tables below). You can add more data to the tables if you want, just follow the PK and FK rules. Accounts are not Loans and Loans are not Accounts. NOTE I already have Answers for part 1 BELOW PART 1 IS FOR ONLY REFRENCE TO ANSWER QUESTIONS 6-11 6- Find Customer ID, Customer name and the number of loans for each Customer. 7- Find Loan number and Customer Id of the loan with the lowest amount. 8- Create a view called Gary_Branch_V that contains Branch Id, Branch name, and number of loans for each Branch that is in the city of Gary. 9- For each Customer in Hopkins, find the balance in their account(s). 10- Find how many different accounts each customer has at each Branch. The output should be a list of Customer ID and for each Customer ID, the number of accounts for this customer by Branch ID. 11- Find the branch with the highest or largest Average loan amount. List the Branch ID, Branch…
- A valid SQL statement should be accepted by a standard SQL interpreter, whereas an invalid SQL statement should result in an error message. Indicate for each of the following SQL statement, whether it is a valid SQL statement or NOT a valid SQL statement. 1. SELECT * FROM ARTICLES WHERE ENDPAGE-STARTPAGE>8;2. SELECT * FROM ARTICLES WHERE ENDPAGE-STARTPAGE<0;3. SELECT SUM (TITLE) FROM ARTICLES;4. SELECT AVG(YEAR) FROM ARTICLES WHERE TITLE LIKE ‘M%’;5. SELECT COUNT(*) FROM ARTICLES GROUP BY YEAR;6. SELECT YEAR, COUNT(*) FROM ARTICLES WHERE COUNT(*)>10 GROUP BY YEAR;Give SQL query to fetch details of employees working in 'IT' department from the table Employee (E_ID, E_NAME, Contact, Department)CREATE the following table on mySQL Consider the following database instance. Table name: Students Primary key: sid Sid sname 7 Ricky 2 Ellen 6 MaryLou 4 Ellen Table name: Courses Primary key: cid cid cname 1 ICS 2 Finance Table name: Register Primary key: sid,cid Foreign key: sid references Students(sid) Foreign key: cid references Courses(cid) sid cid 7 2 2 2 7 1 4 1 check_circle Expert Answer thumb_up thumb_down Step 1 Here have to determine sql statement for given problem. Step 2 Answer,::: Here i have given Sql query statment of your given problem statement. 1) CREATE TABLE Students ( Sid int not null primary key, sname varchar(255) ); INSERT INTO Students (Sid, sname) VALUES (7, "Ricky"), (2, "Ellen"), (6, "MaryLou"), (4, "Ellen") ; 2) CREATE TABLE Courses ( Cid int not null primary key, cname varchar(255) ); INSERT INTO Courses (Cid, cname)…