Your Chi-square analysis has shown that the Chi-square computed value is 0.32 and the Chi-square table value is 7.815. O Reject the alternative hypothesis. Reject the null hypolhesis O Accept the alternative hypothesis
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- The popularity of the chi square test is largely due to what?Although the chi-square homogeneity test and the chi-square independence test use essentially the same basic procedure, the context of the two tests are quite different. Explain the difference.A recent study of 100 individuals found the following living arrangements for men and women. Can it be concluded that there is a dependent relationship between gender and living arrangements at the α = 0.025 level of significance. Use the chi-square test of independence.
- 2. Consider a study where students are measured on whether they had an internship during their time at WKU (Y/N) and whether they had a job at graduation (Y/N). If we wanted to test whether having an internship was associated with having a job at graduation (i.e., internship holders were more likely to have jobs), why would the chi-square test be inappropriate for this hypothesis? How should we analyze our data?The U.S. Department of Labor stated that the national unemployment rate was 4.9%. Of a sample of 90 people in one city, 5.2% were unemployed. Can the city conclude that their unemployment rate is the same as the national average? Do we reject the null hypothesis? (Answer on Excel)Many cities around the United States are installing LED streetlights, in part to combat crime by improving visibility after dusk. An urban police department claims that the proportion of crimes committed after dusk will fall below the current level of 0.84 if LED streetlights are installed. Specify the null and alternative hypotheses to test the police department’s claim.
- According to Johns Hopkins Medicine, the healthcare providers consider a fever to be 100.4◦F. Data was acquired in a health center that observed 24 adults with COVID- 19. We want to find out if the sample mean of 104◦F body temperature of adults with COVID-19 is significantly higher than the body temperature of a person with fever. Consider the sample SD of 10.2◦F.The Florida State University nursing department is running a Chi Squared analysis and have set their significance at 95%. Based on the following statistical statement, χ2(3, N = 248) = 4.37, p < .51, the researchers should fail to reject the null.A newsletter publisher believes that less than 36%36% of their readers own a laptop. For marketing purposes, a potential advertiser wants to confirm this claim. After performing a test at the 0.010.01 level of significance, the advertiser failed to reject the null hypothesis. What is the conclusion regarding the publisher's claim?
- If the calculated value of Chi-square is less than the critical value of Chi-square, would you reject or fail to reject the null hypothesis? Using the .05 level of significance and 4 degrees of freedom, what would the critical value of Chisquare be? BE SURE TO ROUND OFF TO 2 DECIMAL PLACES.Please do the following questions with full handwritten working out. Mean= 0.177911 Variance=0.057632Calculate Pearson’s coefficient of skewness. Hence, describe the shape of thedistribution of the waiting time for counter A and B.