ys É (x₁4₁ 2) = -9x² +10ln(y +1) + 6x² +10y= We have Ex= 1 F₂ = [ [ With x = 2₁ g =0 we have 2 = -
ys É (x₁4₁ 2) = -9x² +10ln(y +1) + 6x² +10y= We have Ex= 1 F₂ = [ [ With x = 2₁ g =0 we have 2 = -
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 2SE: If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local...
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