Question
Asked Nov 22, 2019
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For the attached picture with the equation, decide whether the answer to each problem is correct.  If it is not, identify the issue and solve it correctly for 0 ≤ x < 2 π.  You must show work for this, all answers should be in radians.

Зл
0, п,
sin
1 has the solution x
COs
2
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Зл 0, п, sin 1 has the solution x COs 2

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Expert Answer

Step 1

Given,

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cos x-sin x= 1, 0<x<2T

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Step 2

It is known that,

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cos (x)-sin (x) 2cosx

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Step 3

Then,

...
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-1+cos 0 +x 4 +x2 + x cos 4 cos x 4 2 Зл х%3D 2лп,х%3D2лп+ 2 For the range 0<x<27 Зл 2

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Tagged in

Math

Trigonometry