~5 V25–z2 •5 7. Evaluate Vx2 + y? + 22 dydxdz 3 -5 . 25—22 Јо

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Q: 15. S (9z + 15z* – 8z° +2 + 4) dz 9.

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Q: 3/24- V 12 +3V3

A: √3(6√2 + 1)

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Q: Integrate: S(6z3 — S (6x³ 12г? + 10г — 9) dr

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Q: Let FECT-2,21], foro. Prave that Max -2

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Q: 1- Y(A,B,C,D)={(6,14,4,12,9,11,1,3) 2- Y(A,B,C,D)= E (5,7,13,15,2,10) 3- Y(A,B,C,D)= E…

A: Summation (6,14,4,12,9,11,1,3) = (6+14+4+12+9+11+1+3) = 60

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Q: B) the eignualues of A= 26,人2--9/2,=B then aB =2/b. B=-llc.Be/B--1 = 2

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Q: There are 3 runners in the field practicing for Tokyo 2021 Olympics. During there practice each of…

A: Note:- G.E.M (Gaussian Elimination Method)

Q: for power substitution method, next step is * For Sdz 16 – 5(u²)â + u² -(2udu) 4 – u? r6 – 5u² + u?…

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Q: The colder a substance gets the less its particles move. O True False QuickNav

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Q: Find the value of ZA (0, 1, 4) - - (-24,-2x, 92) dr I= -8 (-1, 4 ,0) BY O a) I = O b) I=2 O c) I =…

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Q: Find u · v. (7, 9) v = (-2, 4) V u.v u:v =

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Q: Зх — Зу — 6z %3D —3 2х — 2у — 4z %3D 10 2х + Зу + z %3 7

A: To Solve the following using Gauss-Jordan Elimination

Q: Evaluate S (vz +va) 1 dz avz.

A: We will solve the integration.

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Q: 7z° Vz7 + 12 da =. (2" – 12)3 +C O 2 (z' + 12) +C O (z7 + 12) + C O 2 (z² + 12) +C (z² + 12) +C 2

A: For the given Intergration .

Q: 3. Simplify: 5/18 – V40 – 2/128 + V90 + 2/3 а. - - b. 4+/12

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Q: 36. f(t) = 10 + 45 t+1

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Q: 1. (1 +V)*dz 2. (22 – 2) dr

A: Solve the following

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A: Here I am attaching image so that you understand each and every step.

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Q: There are 3 runners in the field practicing for Tokyo 2021 Olympics. During there practice each of…

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Q: -- - I- -L - L 3 1.0 -12 8,8) 12 -L-L

A: is the required function.

Q: 12. y"- - -3, 2y-3y- 0, y(4) y'(4) = -17

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Q: 5. Determine S 1 dr Vx? – 3x +5 (i) 1 dr 63+4x 4x2 (ii)

A: Solution

Q: 2. Amelia and Zerin are creating a pattern on the sidewalk with chalk. Amelia starts her pattern…

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Q: write of VV2,V3, where Vas linear Combination. V= (2,7,10), V,= (1,2,3), Vz (1,3,s)3=U,5,9).

A: The given vectors are v=2,7,10v1=1,2,3v2=1,3,5v3=1,5,9 We have to write the vector 'v' in the linear…