   Chapter 12.3, Problem 26E

Chapter
Section
Textbook Problem

# Projectile Motion In Exercises 27-40, use the model for projectile motion, assuming there is no air resistance and g = 32 feet per second per second.Determine the maximum height and range of a projectile fired at a height of 3 feet above the ground with an initial speed of 900 feet per second and at an angle of 45 ∘ above the horizontal.

To determine
The maximum height and range of a projectile fired at a height of 3 feet above the ground with an initial speed of 900 feet per second and at an angle of 45° above the horizontal.

Explanation

Given:

The provided height from the ground, initial velocity and angle is h=3, v0=900  and θ=45

Explanation:

Using theorem,

12.3 with g=32 feet per second producesr(t)=(900cos45)t.i^+[3+(900cos45)t16t2]j^      =4502.t.i^+[3+4502.t16t2].j^

The velocity vector that is,

v(t)=4502.i^+[4502.t32t].j^The maximum height occurs wheny'(t)=0450232t=0t=19

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