Following are the results of a standard penetration test in sand. Determine the corrected standard penetration number, (N1)60, at various depths. Note that the water table was not observed within a depth of 10.5 m below the ground surface. Assume that the average unit weight of sand is 17.3 kN/m3. Depth (m)             N60   1.5                          8 3.0                           7 4.6                          12 6.0                          14 7.5                          13

Q: 3. A Cone Penetration Test result were given in the table below. A. Plot the cone penetration test…

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Q: The following are the results of a standard penetration test in sand. Determine the corrected…

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Q: A civil engineer is interested in assessing the variation of shear strength of clay layers in a site…

A: Given-   shear strength=40 kPa  standard deviation= 15.5 kPa

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Q: Repeat Problem 3.6 using Eq. (3.29).

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A:

Q: Refer to Problem 3.4. Using Eq. (3.28), determine the average relative density of the sand. Assume…

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Q: Question attached

A: Calculate the over consolidation ratio by using the equation. OCR=0.58N60Paσo' …… (1) Here, OCR is…

Q: Refer to Problem 3.4. Using Eq. (3.22), determine the average relative density of sand.

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Q: A soil profile is shown in Figure P3.2 along with the standard penetration numbers in the clay…

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Q: Calculate the theoretical depth of penetration 32 kN/m 3.5 m 90 Clay C = 12 kN/m²

A: Consider the given data H=3.5mP=32 kN/mConsiderqu=15 kN/m2 So here now, P=2q-rH   =2×15   =30 kN/m2

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Q: Following is the variation of the field standard penetration number (N60) in a sand deposit: The…

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Q: Site investigation is to be made for a structure 100m length x 60m width. The soil profile is shown.…

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Q: FUNDAMENTALS OF GEOTECHNICAL ANALYSIS During a Standard Penetration Test on silty clay soil, blow…

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Q: Question attached

A: Standard Penetration Test is mostly used in geotechnical engineering to determine the relative…

Q: Question attached

A: Solution; Given that; pa=100 KN/m2

Q: A civil engineer is interested in assessing the variation of shear strength of clay layers in a site…

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A: Depth qc(MPa) qs(KPa) FR (%) Soil classification 0.5 1.86 22.02 1.19 Silt mixture clayey silt to…

Q: Question attached

A: Solution:

Q: During

A: Date is not a requirement which may be omitted in bore hole drilling record.

Q: 3. A civil engineer is interested in assessing the variation of shear strength of clay layers in a…

A: Step 1

Q: The following standard penetration test results were obtained in a uniform silty sand:Depth (m) 1 2…

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A:

Q: Question attached

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Q: 2- Subsurface geotechnical investigations carried out in a deposit of sand provided the field…

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Q: 2. A cut slope was excavated in sand. The slope is shown in following figure. 18m o. 5 m 14m 30 To…

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Q: 7. Refer to soil profile shown in Fig. 1. If the cone penetration resistance (qe) at 'A' as…

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A: As per company's guidelines we can only answer first question.  Kindly post other question as…

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A: Given : Depth and Standard Penetration Number,N60  B= 1.83 m Df =6.91m Se = 25 mm

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A:

Q: b) Table Q2 provides the result of a standard penetration test in the sandy soil. The water table…

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Q: Q1): The standard penetration test was carried out in a coarse sand at the site of the multi-story…

A: The given data is: Depth (m) Blows/15 cm Blows/15 cm Blows/15 cm Notes   0 - 15 15 - 30 30 - 45…

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.