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Engineering
Mechanical EngineeringInternational Edition---engineering Mechanics: Statics, 4th Edition4th Edition
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Replace the force and the couple with an equivalent force-couple System with the force acting at point B .

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International Edition---engineerin...

4th Edition
Andrew Pytel And Jaan Kiusalaas
Publisher: CENGAGE L
ISBN: 9781305501607

Solutions

Chapter
Section
Problem 3.1P
Problem 3.2P
Problem 3.3P
Problem 3.4P
Problem 3.5P
Problem 3.6P
Problem 3.7P
Problem 3.8P
Problem 3.9P
Problem 3.10P
Problem 3.11P
Problem 3.12P
Problem 3.13P
Problem 3.14P
Problem 3.15P
Problem 3.16P
Problem 3.17P
Problem 3.18P
Problem 3.19P
Problem 3.20P
Problem 3.21P
Problem 3.22P
Problem 3.23P
Problem 3.24P
Problem 3.25P
Problem 3.26P
Problem 3.27P
Problem 3.28P
Problem 3.29P
Problem 3.30P
Problem 3.31P
Problem 3.32P
Problem 3.33P
Problem 3.34P
Problem 3.35P
Problem 3.36P
Problem 3.37P
Problem 3.38P
Problem 3.39P
Problem 3.40P
Problem 3.41P
Problem 3.42P
Problem 3.43P
Problem 3.44P
Problem 3.45P
Problem 3.46P
Problem 3.47P
Problem 3.48P
Problem 3.49P
Problem 3.50P
Problem 3.51P
Problem 3.52P
Problem 3.53P
Problem 3.54P
Problem 3.55P
Problem 3.56RP
Problem 3.57RP
Problem 3.58RP
Problem 3.59RP
Problem 3.60RP
Problem 3.61RP
Problem 3.62RP
Problem 3.63RP
Problem 3.64RP
Problem 3.65RP
Problem 3.66RP
Problem 3.67RP
Problem 3.68RP
Problem 3.69RP
Problem 3.70RP
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International Edition---engineerin...

4th Edition
Andrew Pytel And Jaan Kiusalaas
Publisher: CENGAGE L
ISBN: 9781305501607
Chapter 3, Problem 3.15P
Textbook Problem
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Replace the force and the couple with an equivalent force-couple System with the force acting at point B.

Chapter 3, Problem 3.15P, Replace the force and the couple with an equivalent force-couple System with the force acting at

To determine

Find equivalent force couple system at B

Explanation of Solution

Given Information:

Force 20 N

Moment 6 N-m

Diagram

From diagram, we get coordinates

  A(180,−150,0)B(−300,200,0)C(0,0,210)

  λAC=C→−A→|C→−A→|=−180i+150j+210k (−180) 2+ 150 2+ 210 2=−0.572i+0.477j+0.667kR=20λAC=20(−0.572i+0.477j+0.667k)R=−11.44i+9.54j+13

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Chapter 3 Solutions

International Edition---engineering Mechanics: Statics, 4th Edition
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