   Chapter 3.1, Problem 61E ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343

#### Solutions

Chapter
Section ### Single Variable Calculus: Early Tr...

8th Edition
James Stewart
ISBN: 9781305270343
Textbook Problem

# Find an equation of the normal line to the curve y = x that is parallel to the line 2x + y = 1.

To determine

To find: The equation of the normal to the curve which is parallel to the given line.

Explanation

Given:

The equation of the curve is y=x and the line is 2x+y=1.

Derivative rules:

Power Rule: ddx(xn)=nxn1

Formula used:

The equation of the normal line at (x1,y1) is, yy1=m(xx1) (1)

where, m is the slope of the normal line at (x1,y1) .

Calculation:

Obtain the slope of the normal line.

Given line rewritten as, y=2x+1 and its slope is −2.

Since the required equation of the normal line is parallel to the given line, the slope of the normal line is equal to the slope of the given line.

Therefore, the slope of the normal line is −2.

Obtain the slope of the tangent line by using the slope of the normal line.

Here, the tangent line is perpendicular to the normal line.

That is, if m1 and m2 are the slopes of tangent line and normal line, then m1m2=1.

Therefore, the slope of the tangent line is 1(2)=12.

Obtain the normal line point on the curve.

The derivative of curve y is as follows,

dydx=ddx(x)=ddx(x12)

Apply the power rule and simplify the expression,

dydx=12x

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Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 