2. To solve a rational inequality, we factor the numerator and the denominator into irreducible factors. The cut points are the real of the numerator and the real. denominator. Then we find the intervals determined by the -, and we use test points to find the sign of the rational function on each interval. Let (x + 2)(x – 1) r(x) = (x – 3)(x + 4) Fill in the diagram below to find the intervals on which r(x) 2 0. 3 Sign of x + 2 x - 1 x - 3 x + 4 (x + 2)(x – 1) (x – 3)(x + 4) From the diagram we see that r(x) 2 0 on the intervals , and

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