   Chapter 5, Problem 10TYS ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 9-14, evaluate the definite integral. ∫ − 2 2 ( 3 − 2 x ) 3 d x

To determine

To calculate: The value of the definite integral 22(32x)3dx.

Explanation

Given Information:

The provided definite integral 22(32x)3dx.

Formula used:

The general power rule of integration,

undudxdx=undu=un+1n+1+C

Where u is a function of x constant.

Fundamental theorem of calculus,

abf(x)dx=[F(x)]ab=F(b)F(a)

Calculation:

Consider the provided definite integral,

22(32x)3 dx

Let u=32x. Then,

du=2dx

Multiply and divide by (2)

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