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Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

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BuyFindarrow_forward

Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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Using Properties of Definite Integrals In Exercises 7 and 8, use the values                     0 5           f ( x ) d x   = 6  and    0 5     g ( x ) d x   = 2 to evaluate each definite integral.

(a)                     0 5 2 g ( x ) d x             (b) 5 0 f ( x )         d x  

(c)                     5 5 f ( x ) d x             (d) 0 5 [ f ( x )     f ( x ) ]     d x  

(a)

To determine

To calculate: The value of definite integral 052g(x)dx where,

05f(x)dx=6 and 05g(x)dx=2.

Explanation

Given Information:

The provided values are 05f(x)dx=6 and 05g(x)dx=2.

Formula used:

Properties of definite integral:

abkf(x)dx=kabf(x)dx

Where, k is a constant

(b)

To determine

To calculate: The value of definite integral 50f(x)dx where,

05f(x)dx=6 and 05g(x)dx=2.

(c)

To determine

To calculate: The value of definite integral 55f(x)dx where,

05f(x)dx=6 and 05g(x)dx=2.

(d)

To determine

To calculate: The value of definite integral 05[f(x)f(x)]dx where,

05f(x)dx=6 and 05g(x)dx=2.

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