   Chapter 7.1, Problem 42E ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
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# Finding the Center and Radius of a Sphere In Exercises 39-44, find the center and radius of the sphere. See Example 6. x 2 + y 2 + z 2 − 4 y + 6 z + 4 = 0

To determine

To calculate: The centre and radius of sphere whose equation is x2+y2+z24y+6z+4=0.

Explanation

Given Information:

The equation of sphere, x2+y2+z24y+6z+4=0.

Formula used:

The standard equation of a sphere with centre at (h,k,j) and radius r is,

(xh)2+(yk)2+(zj)2=r2

Calculation:

Consider equation of sphere,

x2+y2+z24y+6z+4=0

Convert the provided equation into the square by grouping the similar variable. So, the above equation can be written as:

x2+(y24y)+(z2+6z)+4=0x2+(y24y)+(z2+6z)=4

To complete the square, add the half of square of each linear term of the equation. So, to complete the square of (y24y), add [12(4)]2=4 on both sides

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