   Chapter 7.8, Problem 4SWU ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919

#### Solutions

Chapter
Section ### Calculus: An Applied Approach (Min...

10th Edition
Ron Larson
ISBN: 9781305860919
Textbook Problem
1 views

# In Exercises 1-12, evaluate the definite integral. ∫ 0 1 2 x 3   d x

To determine

To calculate: The value of definite integral is 012x3dx.

Explanation

Given Information:

The definite integral is 012x3dx.

Formula used:

If x is lower limit & x2 is upper limit then for the above function.

x1x2axndx=a[xn+1n+1]x1x2=a[x2n+1x1n+1n+1]

Calculation:

Considering the function f(x)=axn

Hence, a=2  and n=3

f(x

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