   Chapter 8.2, Problem 40ES Mathematical Excursions (MindTap C...

4th Edition
Richard N. Aufmann + 3 others
ISBN: 9781305965584

Solutions

Chapter
Section Mathematical Excursions (MindTap C...

4th Edition
Richard N. Aufmann + 3 others
ISBN: 9781305965584
Textbook Problem

Encryption. Encode the message by using a cyclical alphabetic encrypting code that shifts the message the stated number of positions.6 positions: FLY TONIGHT

To determine

Encode the message by using a cyclical alphabetical encrypting code that shifts the message the stated number of positions:

6 positions: FLY TONIGHT

Explanation

Given: 6 positions: FLY TONIGHT

Formula Used:

If the encrypted code is to shift each letter of the plaintext message m positions, then the corresponding letter in the cipher text message is given as follows

c=(p+m)mod26

Where p= numerical equivalent of the plaintext letter

c= numerical equivalent of the cipher text letter

Calculation:

The word in plaintext is given as

FLY TONIGHT

Here m=6

Encryption is carried as follows

F   c=(6+6)mod26=12mod26=12   Coded as L

L   c=(12+6)mod26=18mod26=18   Coded as R

Y   c=(25+6)mod26=31mod26=5   Coded as E

T   c=(

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