preview

Camphor Reduction Reaction Lab Report

Decent Essays

The purpose of this experiment was to perform a reduction reaction using camphor in methanol with sodium borohydride. This reaction generated a mixture of diasteroemers; bornoel and isoborneol. NMR analysis was used to determine the product ratio of isoborneol to borneol. In this experiment, 100 mg of camphor, appearing as white crystals, were dissolve in 1 mL methanol. Four portions of approximately 25 mg of sodium borohydride were added. The reaction mixture was refluxed for 5 minutes and cooled to room temperature. The reaction flask was then placed into ice bath and filtrated by vacuum filtration. The mixture of isoborneol and borneol appeared to as a white powder. Camphor is the limiting reagent in this reaction, which will theoretically yield 0.101 g of borneol. In this experiment, .0961 g of bornoel was …show more content…

This is very high yield, which indicate there weren't any errors in this experiment. As seen the calculations, the product ratio between isoborneol to borneol is 3.91. This means that for every 3.91 isoborneol will be 1 borneol. Compared to the example with integration ratio of 2.314 and 9.497, a product ratio of 5.13 was calculated. The product ratios are similar, however, in this experiment much less borneol was found. Even in the NMR displayed in figure A, it was difficult locating the peak B, which represented borneol. Isoborneol is the major product in this reaction because the reaction has favorable mechanism for endo pathway. In this reaction, sodium borohydride acts as nucleophile to the electrophile of the carbonyl on camphor. Sodium borohydride can attack via the endo and exo pathways. In order to attack the exo pathway, the sodium borohydride has to

Get Access