Chemistry Study Guide

As a group, we obtained our salt mixture of calcium chloride and potassium oxalate, and weighed the mixture. We were able to make an aqueous solution from the mixture and distilled water. We boiled and filtered off the solution, leaving the precipitate. Once the precipitate was dried overnight, it was weighed and the mass was measured. Then we calculated the moles of the precipitate.

In this experiment, I was trying to determine the solubility product constant (Ksp) of Lead(II) Chloride. This experiment is important because it will allow me to determine the concentration of ions in an aqueous state from a solute such as Lead(II) Chloride.

A salt concentration of 1562 ppm is equivalent to an electrical conductivity of how many dS/m?

7. In a procedure developed to determine the percent zinc in post 1982 pennies, 50 ml of an HCl solution was used to react (dissolve) all of the zinc in the penny. To ensure complete reaction, the solution contains twice as many moles of HCl that is actually needed. What concentration of HCl should be used?

Chemistry 102 is the study of kinetics – equilibrium constant. When it comes to the study of acid-base, equilibrium constant plays an important role that tells how much of the H+ ion will be released into the solution. In this lab, the method of titrimetry was performed to determine the equivalent mass and dissociation constant of an unknown weak monoprotic acid. For a monoprotic acid, it is known that pH = pKa + log (Base/Acid). When a solution has the same amount of conjugate base and bronsted lowry acid, log (Base/Acid) = 0 and pH = pKa. By recording the pH value throughout the titration process and determining the pH at half- equivalence point, the value of Ka can be easily calculated. In this experiment, the standardized NaOH solution has a concentration of 0.09834 M. The satisfactory sample size of known B was 0.2117 g. The average equivalent mass of the unknown sample was found to be 85.01 g, pKa was found to be 4.69, which was also its pH at half-equivalence point and Ka was found to be 2.0439×〖10〗^(-5). The error was 1.255% for equivalent mass and 0.11% for Ka. In other word, the experiment was very precise and accurate; the identity of the unknown sample was determined to be trans-crotonic by the method of titrimetry.

The last test, which is the hardest of the 3 test, is the alkalinity test. Alkalinity is the name given to the quantitative capacity of all aqueous solution to neutralize an acid. Group P and W’s results were 12 but group A’s results show a 15. The average was 13. The number of rocks that were neutralizing the acid for group P was 24; for group A it was 19; for group W it was 22. All together the number that neutralized acid is 65. Compared to 29, which is the amount of rocks that do NOT neutralize acid, was 69.1% for limestone rocks, which is fairly

Solve the following problem related to the solubility equilibria of some metal hydroxides in aqueous solution.

Ammonia, Drain Cleaner, Detergent, and Baking Soda are the basic household solutions. I can tell from their pH values because they’re greater than 7.

So, Cs equals 300 and i, the ionization constant is 1. The equations are listed below. We then calculated the water potential of both the sucrose solution and the potato tissue. For the second equation, p equals 0 because there is no turgor

My hypothesis was correct. By calculating the average amount of KMnO4 used to titrate (0.01803 L and 0.01262 L), I was able to determine it's amount of moles (0.003606 and 0.003606). From that point, I used the balanced equation (2 KMnO4 + 5 H2O2 + 3 H2SO4 → K2SO4 + 2 MnSO4 + 8H2O + 5 O2) to find the ratio between the KMnO4 and H2O2 (2:5) to get the amount of moles for H202 (0.009015 and 0.00631). Then I simply plugged in that information into the equation for morality (M=m/L) to find the morality of the H2O2 which was 0.9015 and 0.631 respectively. This outcome was to be expected as my hypothesis was based upon the relationship of the KMnO4 and H2O2 in the reaction, so I had to do was find the characteristics of the KMnO4 in the solution

Heat was added to the original solution until potassium nitrate was fully dissolved, then once the solution was cooled and the formation of crystallization appeared the temperature was recored. Using the Ksp and temperatures of crystallization ∆G˚ can be determined for each six points during the experiment where volume is added, using the equation:

The purpose of this experiment is to determine the identity of an unknown solid by measuring its solubility. Solubility is the concentration of a saturated solution. A saturated solution is one that has completely dissolved in water. Another way to define solubility is the maximum mass of solid that can dissolve in 100ml of water at a given temperature. In addition, solubility is a characteristic property, and its units are grams per 100 ml of water. Some key terms to know relating to solubility are the solute and the solvent. The solute is the substance that is being dissolved, while the solvent is the substance that is doing the dissolving. In our experiment, the unknown solid is the solute and the water is the solvent.

The color of the standard solution became a very deep blue color. To find the concentration of the standard solution, the volume of the standard solution was divided by the calculated moles of the Copper Nitrate and

5. Equivalence Point: 24% error, Gravimetric determination: 17% error. The gravimetric determination was more accurate because an exact amount of precipitate was formed.

Table 3 : The time taken for potassium permanganate solution to decolourise in different concentration of glucose solution