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E-Stilbene Lab Report

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(E)-Stilbene is a trans-1,2-diphenyl ethane. When a bromine is added in presence of a double bond, the bromine will be added across a double bond. In this particular case of (E)-Stilbene’s exposure to bromine, there are three possible products that can be produced. The first is called a meso-stilbene dibromide. It is a meso-isomer. The other two products that are enantiomers to each other. Those are the D and L isomers. The D or L isomers are diastereomers towards a meso- isomer. The purpose of this experiment is to verify the predominate stereoisomers and to determine the intermediate cation’s structure. The question is what is the distribution. When bromine is added to (E)-Stilbene, what distribution will be observed in terms of isomers? …show more content…

The most of the product is going to be meso. It will be like 90% meso and 10% D and L. This is the problem in terms of prediction because the prediction was either 100% meso or 50% meso and 50% D and L. There is a way to explain this problem that why the meso product is dominant. Both cations are in the solution at exactly the same time. Therefore, what mentioned here is it’s not one cation or the other. Both of them are forming. If there are two molecules that are essentially the same molecule in different structure, that means they are going to be equilibrium with each other. Now based upon the distribution, a meso product from cyclic intermediate is dominant because there 90% of meso product. Also, the only way to get 90% meso-poduct, a cyclic has to be dominant and favored with little bit of …show more content…

To compared this discrepancy, the percent yield is calculated by dividing actual yield by theoretical yield and multiplying 100. First, the theoretical yield was determined. Originally, 0.92g of (E)-Stilbene was used. Molecular weight of (E)-Stilbene is 180.25g/mol. 0.92g of (E)-Stilbene is equal to 0.0051 mol of (E)-Stilbene (= 0.92g × 1mol/180.25g). Then, 5mL of 1M of Bromine was used as a limiting reagent. The amount of bromine can react with (E)-Stilbene was 0.005mol (=5mL × 1L/1000mL ×1 mol/L). Therefore, the theoretical yield is 0.005mol. For 100% yield, 0.005mol of meso-Stilbene Dibromide will be precipitated. After the experiment, actually, only 0.862g was precipitated. 0.862g of meso-Stilbene Dibromide is equal to 0.00478mol of meso-Stilbene Dibromide (= 0.862g× 1mol/180.25g). The percent yield calculated in this lab is 95.6% (= (0.00478 mol)/(0.005 mol)×100%). The good yield should be in range of 60% and 65%. Since it is above this range, the yield obtained in this lab was extremely good. When vacuum filtering the solid through Buchner funnel, some of the product passed the funnel paper and this might cause the loss of the product. However, the high yield is also possible meaning of presence of

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