Name: Ashley Lee
Class: HLT-362 Applied Statistics for Healthcare Professionals
Date: 04/01/2015
EXERCISE 18 • Mean, Standard Deviation, and 95% and 99% of the Normal Curve
1. Assuming that the distribution is normal for weight relative to the ideal and 99% of the male participants scored between (–53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? Round your answer to two decimal places.
In order to find where 95% of the values for the weight of relative to the ideal lies you would use the formula that is presented in the text on page 132 of Exercise 18. This formula is:. The = MEAN (5.48) and the (SD) =Standard Deviation (22.93). These numbers were derived from table 1 on pg.133 under the column
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To find the 95% of the men’s scores you would again use the formula:. The Mean=52.53 and the SD=30.90. These scores were found on pg. 134 in table 2 column labeled Male in the pain category.
Formula: 52.53±1.96(30.90)
52.53-1.96(30.90) = 52.53-60.56
52.53-60.56= -8.03
52.53+1.96(30.90) = 52.53+60.56
52.53+60.56= 113.09
ANSWER= (-8.03,113.09)
5. Were the body image scores significantly different for women versus men? Provide a rationale for your Answer.
On pg. 133 of the workbook Exercise 18 the body image scores were found to be significantly higher in women versus men. The rationale for this information was stated in the information provided on pg.133 stating that women had a score of (73.1±17.0) and men had a score of (60.2±17.0).
6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the men’s mental health scores around the mean in this distribution? Round your answer to two decimal places.
To find the 99% of the men’s mental health scores you would use the formula:. This formula was found on page 132 of Exercise 18 in the second paragraph. The Mean=57.09 and the SD=23.72. These scores were found on pg. 134 in table 2 column labeled Male in the mental health category.
Formula: 57.09±2.58(23.72)
57.09-2.58(23.72) = 57.09-61.20
57.09-61.20= -4.11
57.09+2.58(23.72) = 57.09+61.20
57.09+61.20= 118.29
ANSWER=
We know that +/- 1.96 standard deviations from the mean will contain 95% of the values. So, we can get the standard deviation by:
2. In order to determine the average amount spent in November on Amazon.com a random sample of 144 Amazon accounts were selected. The sample mean amount spent in November was $250 with a standard deviation of $25. Assuming that the population standard deviation is unknown, what is a 95% confidence interval for the population mean amount spent on Amazon.com in November?
(c) The mean of the sample and the value of Z with an area of 5% in the left tail.
If John gets an 90 on a physics test where the mean is 85 and the standard deviation is 3, where does he stand in relation to his classmates? (he is in the top 5%, he is in the top 10%, he is in the bottom 5%, or bottom 1%)
5. Give the standard deviation for the mean and median column. Compare these and be sure to identify which has the least variability?
Topics Distribution of the sample mean. Central Limit Theorem. Confidence intervals for a population mean. Confidence intervals for a population proportion. Sample size for a given confidence level and margin of error (proportions). Poll articles. Hypotheses tests for a mean, and differences in means (independent and paired samples). Sample size and power of a test. Type I and Type II errors. You will be given a table of normal probabilities. You may wish to be familiar with the follow formulae and their application.
18. Suppose that the scores of architects on a particular creativity test are normally distributed. Using a normal curve table, what percentage of architects have Z scores:
2. For the following set of scores, fill in the cells. The mean is 74.13 and the standard deviation is 9.98.
Garner, David. “The 1997 Body Image Survey Results.” Overall men and women are affected everyday by what social media has to say. It makes people unhappy with who they are and what they look like. Women and men are feeling ashamed about things that really aren't under their control.
This raises the question about gender difference and the concept of body image and prevalence of
Body image is a major concern amongst the majority, primarily the youth of the female population, ranging from as young as five years old to tertiary students, ’74.4% of the normal-weight women stated that they thought about their weight or appearance ‘all the time’ or ‘frequently’’ (Brown University, unknown).
In this research, thematic analysis distinguished the gender difference among age-related and body image concerns. Four sub-categories emerged from the results; the first two categories displayed conceptualization of the body. Men described their bodies as a unit and had a single evaluation of their bodies. Whereas women’s responds were negative and positive, the responds were very detailed and focused more on parts of the body.
The 95% confidence interval for the population mean is 66,438 to 80,241. This means that there is a 95% confidence that this interval has the population mean.