EXPERIMENT: COEFFICIENTS OF FRICTION
Student name: Hoang Minh Nguyen
Student ID: 10560519
TA’s name: Benjamin Bradley Pilgrim
Date: 03/02/2015
Partner’s name: Stephen Moore
I. RESULTS/GRAPHS m (kg)
(block + mass) Fmax
(N) FK
(N) FN
(N)
0.6465 5.549 2.920 6.336
1.1465 7.6 3.628 11.236
1.6465 9.73 5.326 16.136
2.1465 12.14 6.505 21.036
2.6465 13.83 9.844 25.936
Note: mblock = 146.5g
FN = m * g = (mblock + mmass) * 9.8
Calculated results:
µs: µs1 = Fmax/ FN = 5.549/6.336 = 0.876 µs2 = Fmax/ FN = 7.6/11.236 = 0.676 µs3 = Fmax/ FN = 9.73/16.136 = 0.603 µs4 = Fmax/ FN = 12.14/21.036 = 0.577 µs5 = Fmax/ FN = 13.83/25.936 = 0.533
average µs = µs1 + µs2 + µs3 + µs4 + µs5)/5 = (0.876 + 0.676 + 0.603 + 0.577 + 0.533)/5 = 0.653
µk: µk1 = Fk/ FN = 2.920/6.336 = 0.461 µk2 = Fk/ FN = 3.628/11.236 = 0.323 µk3 = Fk/ FN = 5.326/16.136 = 0.330 µk4 = Fk/ FN = 6.505/21.036 = 0.309 µk5 = Fk/ FN = 9.844/25.936 = 0.380
average µk = µk1 + µk2 + µk3 + µk4 + µk5)/5 = (0.461 + 0.323 + 0.330 + 0.309 + 0.380)/5 = 0.361
II. CONCLUSION
1. State the purpose of the experiment.
To measure and analyze the coefficients of friction µs and µk between a wood block and wood plane.
2. What was demonstrated by the results of the experiment?
From the results of the experiment, we obtain the coefficients of static friction and kinetic friction of the wood plane. The calculated results of these two coefficients show that µs of a surface is usually larger
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