In this mathematical circumstance, it is appropriate to use the Normal Model with this data distribution because of how roughly symmetric and unimodal. The summary statistics for the OB Math SAT scores are as follow: the number of values is 287, the mean of the data is 553.62369, the standard deviation is of approximately 65.984512, the median of the data is 540, the range of the data is 390, the minimum value is 360, the maximum value is 750, the first quartile of the data is 510, and the second quartile of the data is 590. To calculate the percent of students that had an SAT math score higher than 560, I used the z-score formula which is z-score= raw score- mean/ standard deviation and plugged the values for each variable. After …show more content…
After solving for the variable and then plugged in the values and I got raw score= 0.8416 (65.984512) + 553.62369 which gave us a raw score of 609 rounded to the nearest integer. To be in the top 5% of the class a student would need to have a SAT score of around 662. I have come to that conclusion by simply converting 5 into a decimal number (5/100) and then plugging that decimal number (0.05) into invNorm in the calculator which gave us invNorm (0.05, 0, 1) = -1.6448. I then changed the number into a positive value to calculate the top 5%, and then plugged it into our raw score formula that we solved earlier and got raw score= 1.6448 (65.984512) + 553.62369 which gave us a raw score of 662 rounded to the nearest integer. To calculate the z-score at the 25th percentile of the model I converted 25 into a decimal number (25/100) and then plugged that decimal number (0.25) into invNorm in the calculator which gave us invNorm (0.25, 0, 1) = -0.6744. Then to calculate the raw score at the 25th percentile I plugged the z-score -0.6744 into the raw score formula we solved earlier and got raw score= -0.6744 (65.984512) + 553.62369 which gave us a raw data value of 509 rounded to the nearest integer. The z-score and raw data value at 75th percentile of the model is 0.6744 and 598. To calculate the z-score at the 75th percentile of the model I converted 75 into a decimal (75/100) and then plugged that decimal number (0.75) into
7. Among freshmen at a certain university, scores on the Math SAT followed the normal curve, with an average of 550 and an SD of 100.
Due to financial hardship, the Nyke shoe company feels they only need to make one size of shoes, regardless of gender or height. They have collected data on gender, shoe size, and height and have asked you to tell them if they can change their business model to include only one size of shoes – regardless of height or gender of the wearer. In no more 5-10 pages (including figures), explain your recommendations, using statistical evidence to support your findings. The data found are below:
2. Describe the pattern of growth in the “Number of people told” column for both Scenario A and Scenario B.
The area under the curve to the left of the unknown quantity must be 0.7 (70%). So, we must first find the z value that cuts off an area of 0.7 in the left tail of standard normal distribution. Using the cumulative probability table, we see that z=0.53.
(a) Then mean of the sample and the value of Z with an area of 10% in right tail.
If John gets an 90 on a physics test where the mean is 85 and the standard deviation is 3, where does he stand in relation to his classmates? (he is in the top 5%, he is in the top 10%, he is in the bottom 5%, or bottom 1%)
standard deviation standardized value rescaling z-score normal model parameter statistic standard Normal model 68-95-99.7 Rule normal probability plot
3. In one elementary school, 200 students are tested on the subject of Math and English. The table below shows the mean and standard deviation for each subject.
2. For the following set of scores, fill in the cells. The mean is 74.13 and the standard deviation is 9.98.
It sounds like using the stratified random sampling would be a good choice for using a particular group of people. In stratified random sampling the individuals conducting the research know some things about the community that is providing date such as age, gender, ethnicity, and medical diagnosis. This is also a good option when there is a time restraint to obtain the information that is being gathered. The survey would also have to be ensured it is written in a way that the average person can clearly understand the question to get a proper answer.
The information in the table below refers to the 2008 model year product line of BMW automobiles. Identify the Individuals, variables, and data corresponding to the variables in the table below. Determine whether each variable is qualitative, continuous, or, discrete. Please refer to problems #51 and #53 on page 13 for examples.
A pharmaceutical company is testing the effectiveness of a new drug for lowering cholesterol. As part of this trial, they wish to determine whether there is a difference between the effectiveness for women and for men. Using = .05, what is the value the test statistic?
number in order from 1 to 100, the make of the car, the price when new
c.)Find a 95% confidence interval for the difference between the above obtained mean starting salaries.
Why does the sampling distribution of the mean follow a normal distribution for a large enough sample size, even though the population may not be normally distributed?