Electrical circuit analysis is done in order to allow the designer to verify his design and to predict the response of the system under varying conditions of load and excitation.…show more content… Its formula looks like this: T= L/R. Tau or lowercase t. Five time constants are required for current to reach 100% of its value. The time constant of t for the circuit in Figure 7.1 is 470 micro seconds.

The Current value of IL, through the inductor at the beginning of the charge cycle is 0 Amps, while, the end of the charging cycle was 10 mA. The voltage at V1 across the inductor and resistor in the beginning stages is 10 V and end with 0V. The inductor acts like an open circuit at the beginning of the charging cycle, ending appearing like a short circuit.

3. Calculation’s verified through MultiSim Program

a. What is the Time Constant for the circuit in Figure 7.1?
470 micro Seconds

b. What is the Transient Time for Figure 7.1? t=0 c. What is the value of the current IL,(should be lowercase L), through the inductor at the beginning and end of the charging cycle?
Beginning is 0 Amps
End is 10^3, 10 mA

d. What is the voltage VL across the inductor and resistor at the beginning and end of the charge cycle?

Beginning is 10 Volts
End is 0 Volts
e. What is VL and IL at 1t, 2t,3t ,4t, and 5t?

1 tau
2 tau
3 tau
4 tau
5 tau
3.67 seconds
1.35 seconds
4.97
micro seconds
18.3
Micro seconds
67.38
Micro seconds

3. Questions related to Constructed Circuit.

a. How does self-resistance of the inductor affect the results?
The magnetic field created by a charging current in the circuit induces a