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Unit 6 Assignment 1-Digit Whole Number

Satisfactory Essays

Step 3: The first clue “Each is a different 1-digit whole number”, I utilized this clue is that I knew 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9 were all 1-digit whole numbers and the six letters had to be one of those ten numbers. The second clue, “All corner numbers are even”, I assumed the problem meant the letters A, C, D, and F had to be even numbers of the 1-digit whole numbers; meaning the four letters would either be 0, 2, 4, 6 or 8. So obviously, B and E could not be even numbers, so they were assigned the odd 1-digit whole numbers, 1, 3, 5, 7, and 9. The third clue, “The product of B and E is 15” looking at the 1-digit odd whole numbers (1, 3, 5, 7, 9), only 2 numbers could multiply to 15. (5 and 3). So B and E could only be 3 or 5. The fourth clue “Half the sum of C and F is 3”, I know that C and F are both corner numbers which means they are even numbers (0, 2, 4, 6, or 8). …show more content…

(0+6 and 4+2). C and F could be 0, 2, 4, or 6. The fifth clue, “C is 2 less than D”, I knew that C and D were both even 1-digit whole numbers. C could only be 0, 2, 4, or 6. Adding two to 0, 2, 4, and 6 would give me D’s possibilities (2, 4, 6, or 8). The last clue, “E is greater than C”, I knew that E could be 3 or 5, so C could not be 6 because that is greater than 3 and

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