Question
Asked Oct 8, 2019
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. A stone is thrown from level zero at 30° above horizontal. It lands at the same level 20 m away.
a. What is the initial speed of the stone?
b. What is the maximum height that it reaches during the flight?
c. How long does the whole flight take?

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Expert Answer

Step 1

Given:

Angle at which stone thrown, θ = 300

Range of the stone = 20 m

20 m
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20 m

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Step 2

Range of the projectile is given by

 

usin 20
R =
where,
u initial velocity
g gravitaional acceleration = 9.8 m/s
R range
0= angle w.r.t horiz ontal
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usin 20 R = where, u initial velocity g gravitaional acceleration = 9.8 m/s R range 0= angle w.r.t horiz ontal

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Step 3

plug in the v...

20 "sin 2(30°)
g
usin(60°)
20
9.8
20x9.8
0.866
u =226.33
u 15.04m/s
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20 "sin 2(30°) g usin(60°) 20 9.8 20x9.8 0.866 u =226.33 u 15.04m/s

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