. Calculate the magnetic dipole moment of a coil of 250 turns, and cross-sectional area of 2.52 x 10-4 m? carrying a current of 100 µA. (express your answer in J/T) . Convert ampere meter square into Joule per tesla ( i.e. A m2 → J/T). : The magnetic dipole moment of the coil is lined up with an external magnetic field whose strength is 0.85 T. How much work would be required to turn the coil? Use u obtained from a.

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Chapter24: Magnetic Fields
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Problem 83A
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Solve in steps please. And what equations do I use?

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a. Calculate the magnetic dipole moment of a coil of 250 turns, and cross-sectional
area of 2.52 x 10-4 m2 carrying a current of 100 µA. (express your answer in J/T)
b. Convert ampere meter square into Joule per tesla ( i.e. A m? → J/T).
The magnetic dipole moment of the coil is lined up with an external magnetic field
whose strength is 0.85 T. How much work would be required to turn the coil? Use
u obtained from a.
С.
Transcribed Image Text:Example a. Calculate the magnetic dipole moment of a coil of 250 turns, and cross-sectional area of 2.52 x 10-4 m2 carrying a current of 100 µA. (express your answer in J/T) b. Convert ampere meter square into Joule per tesla ( i.e. A m? → J/T). The magnetic dipole moment of the coil is lined up with an external magnetic field whose strength is 0.85 T. How much work would be required to turn the coil? Use u obtained from a. С.
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