. Estimate the duration of Deposit NBank Balance SheetCash = $ 50Loan M (7%, 6 years) = $200Deposit N (3 years, 2%) = $ 200Equity = $ 50Total Assets = $250Total Liabilities = $ 250 a.1.94 b. 2.94 c. 3.94 d. 4.94
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. Estimate the duration of Deposit N
Bank Balance Sheet
Cash = $ 50
Loan M (7%, 6 years) = $200
Deposit N (3 years, 2%) = $ 200
Equity = $ 50
Total Assets = $250
Total Liabilities = $ 250
a.1.94
b. 2.94
c. 3.94
d. 4.94
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- . Estimate the duration of Loan MBank Balance SheetCash = $ 50Loan M (7%, 6 years) = $200Deposit N (3 years, 2%) = $ 200Equity = $ 50Total Assets = $250Total Liabilities = $ 250 a. 3.1 years b. 4.1 years c. 5.1 years d. 6.1 yearsIn the following balance sheet, Loan A(8%, 3 year)= $150 Deposit A(5%, 2 years)=$250Loan B(11%, 4 years)= $200 Deposit B(7%, 3 year)= $100Total Assets = $350 Total Liabilities = $350The GAP 3 yr=-200 if all interest rates decrease by 3%, net impact on net interest income (ΔNII) is a. +$6 b. +$7 c. +$8 d. +$9Calculate (a) the interest payable and (b) the total amount owing on the following deposits at simple interest. (i) £2500 invested for 6 months at 8.75% p.a. (T = 05 years)
- Assume a bank has the following balance sheet. Determine the 2-year GAP. AssetAmount LiabilityAmountCash$100 90-day CDs$1006-month Gbonds$400 360-day CDs$200 2-yearcommercialloans$400 Time Deposits 2- year $900 5-year fixedrate loans$500 Stockholder’s equity$200 Total$1,400 Total$1,400 GAP = (RSA2 yr – RSL2 yr) 0 -$100 -$200 -$300 -$800An amortization of a debt is in a form of a gradient series of ₱5,000 on the first year, ₱4,500 on the second year, ₱4,000 on the third year, ₱3,500 on the fourth year. Determine future amount of the amortization if interest is 5%. Ans. ₱18,449.37the difference between the future values of a deposit accumulated for 15years at a rate of 9.5% compounded per annum and the future value of same deposit over the same period at 7.75% compounded quarterly is 375. find tge deposit
- For the case shown in the following table, determine the amount of the equal, end of year deposits necesssary to accumulate the given sum at the end of teh specified period, assuming the stated annual interest rate. Sum to be accumulated Accumulation Period (Years) Interest Rate $124,600 20 11%For ethe case shown in the following table, determine the amount of the equal, end of year deposits necessary to accumulate the given sum at the end of the specified period, assuming the stated annual interest rate. Sum to be accumulated: $130,000 Accumulation Period (years): 30 Interest Rate: 13% The amount of the end of year annual deposit is? (round to the nearest cent)Based on the depositors rate of return as the following tableDeposit TypesRate of return6 months & less6%9 months & less3%12 months & less5%More than 12 months4%determine the profit attributable to the ( A ) depositor who invested OR 44500 from 1st. January 2018 to 15 August 2019
- Your client deposits $10,000, 2% in CD that is matured in 7 years. What is the total earned interest, and ending balance? Please show the supportive calculation and brief interpretation Year 1 10,000 2 456WN 3 Beginning Simple Compound Total Amount Interest Interest 0.00 7 Total Ending Interest Amount 210 $10,200After 22 years of 7.2% interest compounded monthly, an account has ₱502,355. What was the original deposit amount? A. P105,548.5017 B. P103,384.5017 C. P103,584.5017 D. P103,548.5017Calculate the annual percentage yield for a certificate of deposit in the amount of $10,000 that will earn a total of $1,250 in interest during a term of 5 years (assume 365 days per year) Multiple Choice: 1.92% 0.89% 2.38% 12.5%