... #include #include #include /* * Function to check whether two passed strings are anagram or not / int isAnagram(char firstString, char *secondString) { int firstCharCounter[256] = {0}, secondCharCounter[256] = {0}; int counter; // Two Strings cannot be anagram if their length is not equal if(strlen(firstString) != strlen(secondString)) return 0; // count frequency of characters of firstString for(counter = 0; firstString[counter] != '\0'; counter++) { firstCharCounter[firstString[counter]]++; } // count frequency of characters of secondString for(counter = 0; secondString[counter] != '\0'; counter++) { secondCharCounter[secondString[counter]]++; } // compare character counts of both strings, // If not equal return 0, otherwise 1 for (counter = 0; counter < 256; counter++) { if (firstCharCounter[counter] != secondCharCounter[counter]) return 0; } return 1; } int main() { char firstString[100], secondArray[100]; printf("First string? "); gets(firstString); printf("Second string? "); gets(secondArray); if(isAnagram(firstString, secondArray) == 1) printf("%s and %s are Anagrams\n",firstString,secondArray); else printf("%s and %s are not Anagrams\n",firstString,secondArray); getch(); return 0; }

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter6: Modularity Using Functions

Section6.4: A Case Study: Rectangular To Polar Coordinate Conversion

Problem 9E: (Numerical) Write a program that tests the effectiveness of the rand() library function. Start by...

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PLease help me to add a loop that will let program repeat until the user will type 'exit' C language
...

#include <stdio.h>

#include <conio.h>

#include <string.h>

* Function to check whether two passed strings are anagram or not

int isAnagram(char *firstString, char *secondString)

{

int firstCharCounter[256] = {0}, secondCharCounter[256] = {0};

int counter;

// Two Strings cannot be anagram if their length is not equal

if(strlen(firstString) != strlen(secondString))

return 0;

// count frequency of characters of firstString

for(counter = 0; firstString[counter] != '\0'; counter++)

{

firstCharCounter[firstString[counter]]++;

}

// count frequency of characters of secondString

for(counter = 0; secondString[counter] != '\0'; counter++)

{

secondCharCounter[secondString[counter]]++;

}

// compare character counts of both strings,

// If not equal return 0, otherwise 1

for (counter = 0; counter < 256; counter++)

{

if (firstCharCounter[counter] != secondCharCounter[counter])

return 0;

}

return 1;

}

int main()

{

char firstString[100], secondArray[100];

printf("First string? ");

gets(firstString);

printf("Second string? ");

gets(secondArray);

if(isAnagram(firstString, secondArray) == 1)

printf("%s and %s are Anagrams\n",firstString,secondArray);

else

printf("%s and %s are not Anagrams\n",firstString,secondArray);

getch();

return 0;

}

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