..... (a) Construct a discrete probability distribution for the random variable x. x (# of children) P(x) 1 2 3 4 (Round to three decimal places as needed.)
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A: Given : X -1 0 2 5 P (x) 0.10 0.50 0.30 0.10
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A: According to the given information, we haveProbability distribution table is given.
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A: NOTE: As per the guidelines, we are supposed to solve the first three sub parts only. Please repost…
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A: Solution: From the given information, probability distribution for the discrete random variable X is
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A: The formula of expected value is,
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A: Option b) is correct. P(X=3) = 0.19 P(X=11) = 0.15
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A: Solution 0 0.269 0 0 0 1 0.571 0.571 1 0.571 2 0.123 0.246 4 0.492 3 0.031 0.093 9…
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A: Farmula used E(X)=∑xP(X=x)
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A: Explanation of the answer is as follows
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A: We have to find given probability.
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A: ANSWER:-
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A: Here is the solution.
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A: Solution: From the given information, the joint probability distribution is
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A: The joint probability distribution of two discrete random variables X and Y is partly given in the…
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A: P(X>0 and Y<=3) = P(X=2,4 and Y=1,3) =0.02+0.2+0.1+0.1 =0.42 (ans)
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A: Given Data: x=0 x=2 x=4 y=1 0.03 0.02 0.1 y=3 0.15 0.2 0.1 y=5 0.20 0.15 0.05
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A:
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A: Here, X>0 means X=2 and X=4. And Y≤3 means Y=1 and Y=3.
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A: The formula of the expected value is,
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Q: c) Let X be the random variable with the cumulative probability distribution: x < 0 F(x) = {₁ - e-²x…
A:
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A: A probability distribution is an expression that associates each outcome of a statistical experiment…
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