0. A small, rigid object carries positive and negative M 3.50-nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.10 mm) and the negative charge is at the point (1.40 mm, -1.30 mm). (a) Find the electric dipole moment of the object. The object is placed in an electric field E = 4.90 × 10° j) N/C. (b) Find the torque acting on the object. (c) Find the potential energy of the object-field system when the object is in this orientation. (d) Assum- ing the orientation of the object can change, find the difference between the maximum and minimum (7.80 × 10³ î potential energies of the system.

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.6CQ: Consider point A in Figure CQ23.6 located an arbitrary distance from two positive point charges in...
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50. A small, rigid object carries positive and negative
M 3.50-nC charges. It is oriented so that the positive
charge has coordinates (-1.20 mm, 1.10 mm) and the
negative charge is at the point (1.40 mm, –1.30 mm).
(a) Find the electric dipole moment of the object. The
object is placed in an electric field É
4.90 × 10° j) N/C. (b) Find the torque acting on the
object. (c) Find the potential energy of the object-field
system when the object is in this orientation. (d) Assum-
ing the orientation of the object can change, find
the difference between the maximum and minimum
= (7.80 × 10³ î
potential energies of the system.
Transcribed Image Text:50. A small, rigid object carries positive and negative M 3.50-nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.10 mm) and the negative charge is at the point (1.40 mm, –1.30 mm). (a) Find the electric dipole moment of the object. The object is placed in an electric field É 4.90 × 10° j) N/C. (b) Find the torque acting on the object. (c) Find the potential energy of the object-field system when the object is in this orientation. (d) Assum- ing the orientation of the object can change, find the difference between the maximum and minimum = (7.80 × 10³ î potential energies of the system.
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