- 0. UBU 18. If the mean is 225 and the standard deviation is 28 for a normally distributed variable, what is the x vc that corresponds to a z = -0.93? 22| (sz2-リ-

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Chapter1: Combinatorial Analysis
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Please Answer and explain #18
J mu p vulue THat čorresponds Tð 2 = -1.32?
P(ZC -1.32)=0.0939
17. What is the z-score that corresponds to P = 0.9131?
standard divation 0=1
PSZLZ )=131
P(Z Q L)
P= 09131 s1.36
18. If the mean is 225 and the standard deviation is 28 for a normally distributed variable, what is the x va
that corresponds to a z = -0.93?
-6.93 =(x-て2う)125
X= 225 - (0.93)(23) F198.9¢
%3D
%3D
19. If the mean is 19 and a standard deviation is 3.7 for a normally distributed variable, what is the z-sc-
represent the x value of 14.9?
2= x-M
「リ- 4-19
%3D
こ
2 scort =
20. Find the z-score that corresponds to P15?
2.=-1.0364
|-1.03 G4
Transcribed Image Text:J mu p vulue THat čorresponds Tð 2 = -1.32? P(ZC -1.32)=0.0939 17. What is the z-score that corresponds to P = 0.9131? standard divation 0=1 PSZLZ )=131 P(Z Q L) P= 09131 s1.36 18. If the mean is 225 and the standard deviation is 28 for a normally distributed variable, what is the x va that corresponds to a z = -0.93? -6.93 =(x-て2う)125 X= 225 - (0.93)(23) F198.9¢ %3D %3D 19. If the mean is 19 and a standard deviation is 3.7 for a normally distributed variable, what is the z-sc- represent the x value of 14.9? 2= x-M 「リ- 4-19 %3D こ 2 scort = 20. Find the z-score that corresponds to P15? 2.=-1.0364 |-1.03 G4
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