µ = 0.01 H/m SW2 50 cm L R N = 100 12V 0.5 Core Area: 0.06 m²

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 9PP: In an R-L parallel circuit, ET=240 volts, R=560 R = 560 2, and XL=330. Find reactive power.
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Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core cross section area A, and core diameter are given. Note that the core length l is equal to π times the core diameter. Answer the questions and pick an answer from the given choices.

Once fully charged, SW2 is closed at the same time SW1 is opened. Nearly how long will it take for the inductor to self-discharge though its own coil resistance?

a) 1h 22 min

b) 10.2 min

c) 55 sec

d) 18.5 min

Sw2
SW, m
H = 0.01 H/m
N = 100
50 cm
R.
12V
Core Area: 0.06 m?
#0.5
Figure 3 (Problem 3)
Transcribed Image Text:Sw2 SW, m H = 0.01 H/m N = 100 50 cm R. 12V Core Area: 0.06 m? #0.5 Figure 3 (Problem 3)
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