01 - Multiplication Times Table Print a multiplication times table from 0 to a user entered number 1less than 10. output should line up appropriately The table should be well-formatted as in the examples and the Enter an integer: 3 O 1 2 3 1 0 1 2 3 2 0 2 4 6 3 0 9 Enter an integer: 8 O 1 2 3 4 7 8. 0 0 0 0 1 0 1 2 3 4 5 6 2 0 2 4 6 8 10 12 14 16 3| 0 3 6 9 12 15 18 21 24 4| 0 4 8 12 16 20 24 28 32 5| 0 5 10 15 20 25 30 35 40 8. 6| 0 6 12 18 24 30 36 42 48 7| 0 7 14 21 28 35 42 49 56 8| O 8 16 24 32 40 48 56 64

01 - Multiplication Times Table Print a multiplication times table from 0 to a user entered number 1less than 10. output should line up appropriately The table should be well-formatted as in the examples and the Enter an integer: 3 O 1 2 3 1 0 1 2 3 2 0 2 4 6 3 0 9 Enter an integer: 8 O 1 2 3 4 7 8. 0 0 0 0 1 0 1 2 3 4 5 6 2 0 2 4 6 8 10 12 14 16 3| 0 3 6 9 12 15 18 21 24 4| 0 4 8 12 16 20 24 28 32 5| 0 5 10 15 20 25 30 35 40 8. 6| 0 6 12 18 24 30 36 42 48 7| 0 7 14 21 28 35 42 49 56 8| O 8 16 24 32 40 48 56 64

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Description: Code this in java 01 - Multiplication Times TablePrint a multiplication times table from e to a user entered number less than 10.output should line up appropriatelyThe table should be well-formatted as in the examples and theEnter an integer: 30 1 2

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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6.32 LAB: Fibonacci sequence The Fibonacci sequence begins with 0 and then 1 follows. All subsequent values are the sum of the previous two, ex: 0, 1, 1, 2, 3, 5, 8, 13. Complete the fibonacci() function, which has an index n as parameter and returns the nth value in the sequence. Any negative index values should return -1. Ex: If the input is: 7 the output is: fibonacci(7) is 13 Note: Use a for loop and DO NOT use recursion. Use Python, please.
•is Valid Phone Number(): ReturnsTrue if the provided phone number (represented as a string) is cor-rectly formatted, otherwiseFalse. To be considered correctly formatted, phone numbers must bewritten as###-###-####, where#is a digit between 0 and 9 .•validatePhoneBook(): A phone book is a list where each entry is a phone book record (represented asa dictionary; see below for more details). This function checks each phone book record in the phonebook for correctly formatted phone numbers.A phone book record is a dictionary which initially has two keys: the key"name"mapped to thecontact’s name (string) and the key"phone number"mapped to that contact’s phone number (alsoa string).validatePhoneBook()adds a new key"valid"to the record with the valueTrueif the phonenumber is formatted correctly, otherwiseFalse. 1. Write white-box and black-box tests for the function is ValidPhoneNumber(). You should do this with-out Python, either on paper, or in a simple document. Don’t worry about…
In Python, grades_dict = {'Wally': [87,96,70], 'Eva': [100,87,90], 'Sam': [94,77,90], 'Katie': [100,81,82], 'Bob': [83, 65, 85]} Ask user to enter the names of the rows, i.e., indices. You can use: len(grades) to get the number of rows of the DataFrame. In addition, using the sort_index() method, ask user whether they wish to sort by rows or by columns and whether to sort in ascending or descending order (do not use any if-else statements)
*4.15 (Phone key pads) The international standard letter/number mapping found on the telephone is shown below:Write a program that prompts the user to enter a lowercase or uppercase letter and displays its corresponding number. For a nonletter input, display an invalid input message. Here are sample runs: Welcome to PhoneKeypad Mapping Program by Mrs Jackson Enter a letter from phone keypad: 2 ** INVALID INPUT !! ** ---------------------------------------------------------------------------------------------- Welcome to PhoneKeypad Mapping Program by Mrs. Jackson Enter a letter from the phone keypad: F *The corresponding letter is 3
#include <iostream> using namespace std; int main() { string c_name ; string car_n; int n, member_n , total ,d; char choice; cout<< "Muscat Auto Workshop"<<endl<<endl; cout<< "Enter customer name : ";cin>>c_name; cout<<" Enter car plate number : ";cin>>car_n; cout<<" choice the required service "<<endl; cout<<" 1-Basic Tuning : 50 OMR "<<endl; cout<<" 2-Software Re-installation : 60 OMR "<<endl; cout<<" 3-Parts Replacement : 100 OMR"<<endl; cout<<" 4-Body Paint : 120 OMR"<<endl; cin>>n; if(n==1) { cout<<" charges before discout = 50 OMR "<<endl; } else if ( n==2) { cout <<" charges before discount = 60 OMR "<<endl; }else if (n==3) { cout<<" charges before discount = 100 OMR "<<endl; }else if (n==4 ) { cout<<" charges before discount = 120 OMR"<<endl; } cout<<" Do you…
Transcribed Image Text Develop a C++ code to computer the queries in X Y z format where you are given a list of size m. For computing queries, you have to perform the task to find the number which is occurring one after another in the sub-list [X Y] greater than or similar to z times. If there doesn't exist no number satisfying the given criteria then output “Not possible" other than that output the answer computed to the given queries. Test Case Result 4 1 2133 121
//main.cpp #include "Person.h"#include "Seller.h"#include "Powerseller.h"#include <iostream>#include <list>#include <fstream>#include <string> using namespace std; void printMenu();void printSellers(list<Seller*> sellers);void checkSeller(list<Seller*> sellers);void addSeller(list<Seller*> sellers);void deleteSeller(list<Seller*> &sellers); int main() { list<Seller*> sellers; ifstream infile; infile.open("sellers.dat"); if (!infile) { cerr << "File could not be opened." << endl; exit(1); } char type; while (!infile.eof()) { infile >> type; if (type == 'S') { Seller* newseller = new Seller; newseller -> read(infile); sellers.push_back(newseller); } if (type == 'P') { Powerseller* newpowerseller = new Powerseller; newpowerseller -> read(infile); sellers.push_back(newpowerseller); } } infile.close();…
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R7.4Explain the mistakes in the following code. Not all lines contain mistakes. Each line depends on the lines preceding it. 1 double a = 1000; 2 double* p = a; 3 int* p = &a; 4 double* q; 5 *q = 2000; 6 int* r = nullptr; 7 *r = 3000;
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