04 Answer with all details, find the area of shaded region in beside shape. sec t y= 1- t2 77

Q: 01 Answer with all details, By y = sin x Using Two method, find the area of shaded region in beside…

A: Are of a bounded curve =∫ydx.

Q: Find the area of the shaded region Blank 1 Note: Enter exact answer x = y 20 1000 y? 20

A: x=yx=1000y2Solve both the equationsy=1000y2y3=1000y=10The limits of y are from 10 to 20.

Q: Sketch the region enclosed by y = e5, y = e®², and x 1. Find the area of the region. ||

A:

Q: Find the area bounded by the indicated curves. y=6-6x, y=D0 The area is square units.

A: The given curves:y=6-6x2, y=0We need to find the area bounded by the given curves.

Q: Find the area of the shaded region. r = Vē 9n?

A:

Q: Find the area of the shaded region. V2 y = csc e cot è 0- 3x - 2

A:

Q: Find the area of the shaded region shown below. YA y = -x? + 4x y = x2 - 2x

A:

Q: Q3/ Find the area of the region that lies inside r=3 sin0 and outside r 2-sin0

A: We'll answer the first question since the exact one wasn't specified.  Please submit a new question…

Q: 22. Find the area enclosed by the curve r²-4coss. c. 16 B. 8 D. 2

A: Given equation of the curve is r2=4cosθ. We know that, area under the curve is given by A=∬Rrdθdr.

Q: Find the area enclosed by the curve 5y? = 16x and y² = 8x – 24. Answer: sq. u.

A: Please go through the attached solution. I hope that this solution will help you. Thankyou . Best…

Q: b) Find the area of the region enclosed between the curves y2 x -1 and y= x-3? (Sketch the region)

A: Solution:-

Q: y=V.r+ 2 www r= 2

A:

Q: y y=5x 1 y=66-x

A: Area of shaded region is 115.33

Q: y = sin(x), y = 5x, x = ?/2, x = ? Find the area of the region

A: consider the given functions, y=sinx and y=5x over the interval x=π2 to x=π draw the graph of the…

Q: Find the area of the shaded region below. yA x= y? – 4y (-3, 3) x = 2y – y? Area =

A:

Q: Find the area of the shaded region below. x= y? – 4y (-3, 3) x= 2y – y?

A:

Q: B: Find the area of the shaded region show y y =1+x X=-1- y=-1 Fig(1)

A: According to the given below figure:  area of the shaded region is…

Q: Sketch the region enclosed by y=e^4x,  y=e^8x and x=1. Find the area of the region.

A: Given curves are  y=e4x, y=e8x and x=1. The graph is

Q: 2x y = x²+4 1 x =-2 x = 2

A:

Q: Find the area of the shaded region. 44) 2) (II/4, 2) TE: II II 2 311 4 y = 2 y = csc²x X

A:

Q: To find the blue shaded area above, we would calculate: | {(2)dz = area Where: b = f(x) = Area = 2.…

A: Solve the following

Q: Find the area of the shaded region.

A: Consider the provided region, Find the area of the region.

Q: Sketch the region enclosed by y = eš", y = e4", and x = 1. Find the area of the region.

A:

Q: 27. Find the area enclosed by the curve r = a (1 - sin e). A B. 2a² C. 3a² D.

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Q: 10 -1.2 dx

A:

Q: 25. yA y = y = V1 – x

A: We have to find the area of the shaded region of the image.

Q: Find the area between the curves y? = -12x and y? = - 24x – 36.

A: y2=-12x,  y2=-24x-36 find intersection points -12x=-24x-36 -12x+24x=-36 12x=-36 x=-3 . y2=-12x…

Q: 10z Sketch the region enclosed by y = 5, y = el, and a = 1. Find the area of the region.

A:

Q: Find the area of shaded region frx)- メ+3 grx)= -x²_ 3 Alx) 3 gre a) 176 3 5) = 88 C) 44 3.

A:

Q: 3x 4x e, y = e", and Sketch the region enclosed by y = x = 1. Find the area of the region.

A:

Q: 6x Sketch the region enclosed by y = e", y = e0", and x = 1. Find the area of the region.

A: Consider the given curves y=e5x,y=e6x, and x=1. Obtain the intersection point as follows.…

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x² + 1 A y = x 4

A: Please refer the attached image for complete solution. THANK YOU.

Q: b) Find the area of the region enclosed between the curves y = x-1 and y= x-3? (Sketch the region)

A:

Q: Use integration and trigonometric substitution to find the area enclosed by the ellipse: y? 81 49

A: The equation of the given ellipse when compared with the standard equation gives the constants as,

Q: Determine the area enclosed by the curve r² = 4a²cos3θ a. 4a² b. 8a² c. 16a² d. a²

A: Given: The polar equation r2=4a2cos3θ To find the area enclosed by the curve r2=4a2cos3θ Symmetry in…

Q: Evaluate (x – 13)dA where Ris the region in the first quadrant enclosed between y = x and y = x'.

A:

Q: Find the area of the shaded region. NOTE: Enter the exact answer. y = x2 + 2 %3D y = x 4.

A:

Q: Q1 Answer with all details, By y = sin x Using Two method, find the area of shaded region in beside…

A: Area under curve

Q: Find the total area of the shaded region below. y y = sec?t 2 1 21 - 3 3 y = -4sin?: -4

A: Solve the following

Q: 04 Answer with all details, find the area of shaded region in beside shape. sec't y= 1- t² t 1 Add…

A:

Q: Find the area of the shaded region. The image is not to sca y = F y=- Consider c=4. Enter the exact…

A:

Q: Find the area of the shaded region. Edit = Vco r = COs 20 r = 2 cos 0 NOTE: Enter the exact answer.…

A:

Q: Find the area of the shaded region below. yA x= y? – 4y (-3, 3)– x= 2y – y? Area =

A: We have to find the the area of the shaded region in the given figure.

Q: Find the area of the region that lies inside the curve but outside the curve 6) 3sine r = 2 - sin0 r…

A: Given the two curve.

Q: Sketch the region enclosed by y = e3, y = e0*, and a = 1. Find the area of the region.

A:

Q: Find the area of the region that lies inside the first curve and outside the second curve. r= 7-7…

A: SOLUTION-

Q: Find the area of the shaded region Blank 1 Note: Enter exact answer x = y 20 1000 y? 20 ||

A:

Q: Q3/ Find the area of the region that lies inside r=3 sin0 and outside r=2-sin0

A:

Q: The radius of gyration of the area shown about the x axis is: Y 4 2. 3.

A:

Q: 04 Answer with all details, find the area of shaded region in beside shape. sec't y 1-12 4

A: Area between curves

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.