1 -2 - 1 b, Let A = - 4 4 and b = b2 Show that the equation Ax = b does not have a solution for all possible b, and describe the set of all b for which Ax = b 4 b3 does have a solution. How can it be shown that the equation Ax =b does not have a solution for all possible b? Choose the correct answer below. A. Row reduce the matrix A to demonstrate that A does not have a pivot position in every row. B. Find a vector x for which Ax = b is the zero vector. O C. Row reduce the matrix A to demonstrate that A has a pivot position in every row. ]« D. Row reduce the augmented matrix Ab to demonstrate that A b has a pivot position in every row. O E. Find a vector b for which the solution to Ax = b is the zero vector. Describe the set of all b for which Ax = b does have a solution. (Type an expression using b,, b2, and bz as the variables and 1 as the coefficient of bą.)

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