1 2 3 4 5 6 The pedigree above displays the inheritance of dominant condition P. Assuming that marker-disease gene linkage (theta) 0.05, what are the probabilities for an individual parental gamete, and an individual recombinant gamete, respectively?
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- The genotype at one CODIS Core Locus for the mother is (3,8) and for the father is (5, 7). Answer the questions below as they relate to that one CODIS Core Locus. Show your calculations and explain your logic. What is the probability the sons will show one matching allele to each other? If a forensic profile is (7, 8) for this CODIS Core locus, what is the probability that one of the two sons will match at both alleles and the other will match at just one allele?Phenylketonuria (PKU) is an inherited disease caused by a recessive allele. Individuals with PKU have two recessive alleles and have very low levels of an enzyme that is needed to properly break down proteins. If a woman and her husband are both carriers and have three children, what is the probability of each of the following? Show your math. (Hint: You can represent your probabilities as fractions or decimals, but probabilities are always between 0 and 1) a. All three children are of normal phenotype. b. One or more of the three children have the disease. c.All three children have the disease.how did we get the number 1x10^6？and 3.98x10^-8？explain？？where these number come from？
- The equation p2+ 2pq + q2= 1 representing theHardy-Weinberg proportions examines genes withonly two alleles in a population.a. Derive a similar equation describing the equilibrium proportions of genotypes for a gene withthree alleles. [Hint: Remember that the HardyWeinberg equation can be written as the binomialexpansion (p + q)2.]b. A single gene with three alleles (IA, IB, and i) isresponsible for the ABO blood groups. Individualswith blood type A can be either IA IAor IA i;those with blood type B can be either IB IBor IB i;people with AB blood are IA IB, and type O individuals are ii. Among Armenians, the frequency of IAis0.360, the frequency of IBis 0.104, and the frequencyof i is 0.536. Calculate the frequencies of individuals in this population with the four possible bloodtypes, assuming Hardy-Weinberg equilibrium.In Problems 15–17, you will see that because matingbetween individuals within populations at Hardy-Weinbergequilibrium is random, it is possible to predict…In human blood types, what are the genotypes of the following parents? 1. Phenotypes of Parents A x AB Phenotypes of Offspring A 1/2 B 0 AB 1/2 O 0 Genotypes of Parents _________ x ________ 2. Phenotypes of parents. A x AB Phenotypes of offspring  A 1/2 B 1/4 AB 1/4 O 0 Genotypes of the parents _________ x ________ 3. Phenotypes of parents. A x A Phenotypes of offspring A 3/4 B 0 AB 0 O 1/4 Genotypes of the parents _________ x ________ 4. Phenotypes of parents. A x O Phenotypes of offspring A 1/2 B O AB O O 1/2 5. Phenotypes of parents. A x B Phenotypes of offspring A 1/4 B 1/4 AB 1/4 O 1/4 Genotypes of the parents _________ x ________ Genotypes of the parents _________ x ________E. W. Lindstrom crossed two corn plants with green seedlings and obtained the following progeny: 3583 green seedlings, 853 virescentwhite seedlings, and 260 yellow seedlings . Q. Give the genotypes for the green, virescent-white, and yellow progeny.
- From the pedigree shown here, answer the following questions with regard to individual VII-1. A. Who are the common ancestors of her parents? B. What is the inbreeding coefficient for this individual?Monozygotic (MZ) twins have a concordance value of 44% for a specific trait, whereas dizygotic twins have a concordance value of less than 5% for the same trait. What could explain why the value for MZ twins is significantly less than 100%?The gel image below shows 7 alleles, let’s call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. In this sample of 11 individuals, how many times does allele 5 appear?
- I have seen that this was answered as C, Why is the answer C, how is that not evidence of it being genetic? Shouldnt it be none of the above? Question: Of the following, which supports the idea that alcoholism has no genetic or a low genetic component? a) Some strains of mice select alcohol over water 75% of the time, whereas others shun alcohol. b) The concordance value is 55% for MZ twins and 28% for DZ twins. c) Biological sons of alcoholic men who have been adopted have a rate of alcoholism more like that of their adoptive fathers. d) There is a 20% to 25% risk of alcoholism in the sons of alcoholic men. e) None of these.If the chi-square value came out to 14,224.221 and the p-value was said to be less than 0.01, what do you conclude about whether these traits follow a simple Mendelian inheritance pattern? Explain your answer.The complete absence of one or more teeth (tooth agenesis) is a common trait in humans—indeed, more than 20% of humans lack one or more of their third molars. However, more severe tooth agenesis, defined as the absence of six or more teeth, is less common and is frequently an inherited condition. L. Lammi and colleagues examined tooth agenesis in the Finnish family shown in the pedigree below. Q.If III-2 and III-7 married and had a child, what is the probability that their child would have tooth agenesis?