1-28. (a) Determine the moment of the 260-lb forces of Fig. P1-28 with respect to point when (1) the force is resolved into components at B; (2) the force is resolved into com ponents at C. (b) By means of the principle of moments determine the perpendicular distance from the force to point A.
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- The cable of the tower crane is subjected to 840 N force, the magnitude of the moment of the force F about A is. Hint: Determine the moment of the force 'F' in Cartesian Vector Form, then deduce the magnitude.  Select one: a. 7920 N.m b. -5040 N.m c. 12979.98 N.m d. 18840 N.miv )Determine the angle of the resultant force, FR (answer in degree) v) Determine the total moments created by the force components about point 0. ( answer in newton meter)The motorcycle weighs 151 kg and the driver weighs 64 kg. Dimensions: l1 = 0,31 m and l2 = 0,23 m Determine the support force on the rear tire. ( DISCLEIMER: I have allready tried to solve this question before and I have been getting 1307.10N as answer. Seems like this answer is not right.)
- Determine the absolute value of the force at point O in [N] ? m = 30 kg F=422 N w = 8 rad/sDetermine the magnitude of the resultant force acting on the shaft shown from left. choices are as follows: a)1450N b)150N c)1650N d)1250NThe rigid pipe is subject to the following loads. Neglecting the weight of the pipe, determine the moment at O. SOLVE THE FF Vector component form of 50-lb force (ANSWER: 25.000i +0j -43.30k lb) Magnitude of the resultant force (ANSWER: 78.10 lb) Position vector of the 50-lb force from point O to its point of application on the pipe. (ANSWER: -15i -10j +12k inch) Moment at point O, in vector component form. (ANSWER: 1153.01i -829.52j +250.00k lb-in)
- Q13. As shown in the image below, the member is subjected to the applied loads: a free couple moment M=320lb*ft, concentrated force F1=380lb, and concentrated force F2=220lb. The dimension a=5.5ft. Determine the magnitude of the resulatant moment (in lb*ft) caused by these applied loads about point A. Answer must inculde 1 place after the decimal point.Given the figure, answer the following multiple choice questions1) Which of the following best approximates the moment of force P about point B? A. 33.6 kN-m CW B. 44.8 kN-m CW C. 56 kN-m CW D. 156.8 kN-m CW2) Which of the following force-couple sets applied at point A is equivalent to the loadings acting on bent bar ABC? A. FA = 2kN down; CA = 19.8 kN-m CW B. FA = 8kN down; CA = 92.2 kN-m CCW C. FA = 2kN down; CA = 61.8 kN-m CW D. FA = 8kN down; CA = 156.8 kN-m CWA force of 800 kN is applied at point B and is directed towards point F. The Force at D = 0 and does not apply. Determine the component of the force that acts in the direction of line BE. Write this component as a Cartesian vector. The answer is (299i-598j+199k) kN, please show in depth how to solve.
- The peg at point B holds the two ropes BA and BC which supports the outdoor canopy. Rope BA is under tension with a magnitude of 375 N. Determine the following: A. The angle between rope BA and the peg. B. The vector component of the projection of tension force in rope BA on the peg. Consider the following dimensions: h1 = 11 m h2 = 0.38 m w1 = 2 m w3 = 0.55 m w2 = 2.8 m d2 = 2.2 m d1 = 1.1 m1. If the resultant force acting on the hook is FR = { -115 i + 643 j + 139 k } lb, determine the magnitude of the force FR in lb.A man on the wire singing "Man on a Wire" while practicing for his circus show has reached the center of the rope, creating a dip on the center angled at 67.87 degrees. If the mass of the man is 42.23 kg and the tension force that can be handled by the wire is 301.26 N, would the wire break? Show the tension caused by the man hanging on the wire. (with illustration)