Determine the maximum height above point A reached by the rocket. (You must provide an answer before moving on to the next part.)
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- (a) Explain briefly the principle of the conservation of Linear Momentum(b) A pile driver, mass 1 tonne, falls freely through a distance of 5m before striking the pile, mass 0.5 tonnes. When the pile is nearly fally driven, the average resistance is 700kN. Determine the penetration per blow at that stage and evaluate the kinetic energy lost at impactA car traveling at 13.7 meters per second crashes into a barrier and stops in 0.280 meters. a. How long does it take the car to stop? Include units in your answer. More information. Hint: This is a constant acceleration problem. b. What force must be exerted on a child of mass 25.8 kilograms to stop him or her in the same time as the car? Include units in your answer. More information. Hint: This is an impulse-momentum theorem problem. c. How many times the weight of the child is this force?A model rocket is launched from point A with an initial velocity, V₀, of 85 m/s. If the rocket’s descent parachute does not deploy and the rocket lands 100 m from A, 1. Determine the angle α that V₀ forms with the vertical. a. 3.90˚ b. 2.35˚ c. 2.25˚ d. 5.25˚ 2. Determine the maximum height, h, reached by the rocket. * 1 point a. 815 m b. 366 m c. 129 m d. 194 m 3. Determine the duration of the flight. a. 13.4 sec b. 17.3 sec c. 11.6 sec d. 10.4 sec
- A volleyball is hit when it is 4 ft above the groundand 12 ft from a 6-ft-high net. It leaves the point of impact withan initial velocity of 35 ft / sec at an angle of 27 and slips by theopposing team untouched. Suppose that the net is raised to 8 ft. Does this change things? Explain.A student on the ground fires a pebble from a catapult with a velocity of 30 m/s at an angle of 30° above the horizontal. If the pebble’s flight is interrupted by a vertical wall 12 m away from the student, at what height above the ground does the pebble hit the wall?When a volleyball coach releases a volleyball from a height of 2 m above the gym floor, it falls to the floor and bounces back to two-thirds the same height. When it is in contact with the floor, the lower side of the ball is temporarily flattened. Suppose the maximum depth of the dent is 1 cm. (Assume the positive direction is upward.)1. Determine the acceleration of the ball (in m/s2) while it is in contact with the floor and compressing. (Indicate the direction with the sign of your answer.) 2. Determine the velocity of the ball (in m/s) as it leaves the floor on the rebound. (Indicate the direction with the sign of your answer.) 3. What If? If instead of dropping the ball, the coach throws it down (from some unknown height) with such a speed that it bounces back up to a height three times its original height, determine the new acceleration of the ball (in m/s2) while in contact with the floor and expanding. (Indicate the direction with the sign of your answer.)
- An automated storage/retrieval system has four aisles. The storage racks in each aisle are 40 ft high and 200 ft long. The S/R machine for each aisle travels at a horizontal speed of 400 ft/min and a vertical speed of 60 ft/min. If the pick-and-deposit time = 0.3 min, determine the throughput rate (loads moved/hr) of the AS/RS, under the assumption that time spent each hour performing single-command cycles is twice the time spent performing dual-command cycles, and that the AS/RS operates at 90% utilization.Angular Momentum of a Particle Two identical spheres with m=3 kg each are rigidly attached to the rotating light rigid structure. The velocity of the spheres is v=2 m/s. Determine the angular momentum about the axis of rotation.Part A: What is the period of the spacecraft's orbit? T=___s Part B: Using conservation of angular momentum, find the ratio of the spacecraft's speed at perigee to its speed at apogee. (Vperigee)/(Vapogee)=___ Part C: Using conservation of energy, find the speed at perigee and the speed at apogee. Vperigee,Vapogee=___m/s Part D: It is necessary to have the spacecraft escape from the earth completely. If the spacecraft's rockets are fired at perigee, by how much would the speed have to be increased to achieve this? delta(perigee)=___m/s Part E: What if the rockets were fired at apogee? delta(apogee)=___m/s Part F: Which point in the orbit is more efficient to use and why?
- A rocketship has 9 modules each with a mass of 15 200 kg and moves at a speed of 7.0 km/s. One of the modules is explosively propelled away from the rocketship at a speed of 1350 km/h with respect to the rocketship, opposite in direction from the original travel direction of the rocket ship.What is the resulting change in the speed of the rocketship?Oblique Impact To analyze an oblique impact using the conservation of momentum and coefficient of restitution. When an oblique impact occurs between two smooth particles, the particles move away from each other with velocity vectors that have unknown directions and unknown magnitudes. If the y axis is within the plane of contact and the x axis is the line of impact, the impulsive forces of deformation and restitution act only along the line of impact (the x axis). Momentum of the system is conserved along the line of impact (the x axis): ∑m(vx)1=∑m(vx)2 The coefficient of restitution, e, relates the relative-velocity components of the particles along the line of impact (the x axis): e=(vBx)2−(vAx)2(vAx)1−(vBx)1 The momenta of both particles A and B are conserved in the plane of contact (the y axis) because no impulse acts on either particle in this plane. Therefore, the y component of the velocities before and after the collisions remains unchanged: Immediately after the collision,…Oblique Impact To analyze an oblique impact using the conservation of momentum and coefficient of restitution. When an oblique impact occurs between two smooth particles, the particles move away from each other with velocity vectors that have unknown directions and unknown magnitudes. If the y axis is within the plane of contact and the x axis is the line of impact, the impulsive forces of deformation and restitution act only along the line of impact (the x axis). Momentum of the system is conserved along the line of impact (the x axis): ∑m(vx)1=∑m(vx)2 The coefficient of restitution, e, relates the relative-velocity components of the particles along the line of impact (the x axis): e=(vBx)2−(vAx)2(vAx)1−(vBx)1 The momenta of both particles A and B are conserved in the plane of contact (the y axis) because no impulse acts on either particle in this plane. Therefore, the y component of the velocities before and after the collisions remains unchanged: (vy)1=(vy)2 As shown,…